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physicslove22
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Homework Statement
The electric field has been measured to be horizontal and to the right everywhere on the closed box shown in the figure. All over the left side of the box E1 = 80 V/m, and all over the right, slanting, side of the box E2 = 400 V/m. On the top the average field is E3 = 260 V/m, on the front and back the average field is E4 = 200 V/m, and on the bottom the average field is E5 = 230 V/m.
Homework Equations
Flux = |E|*|A|*cos (theta)
ε0 = 8.85 ✕ 10-12 C2/N·m2
The Attempt at a Solution
The flux on the sides of the box = 0 because the electric field is perpendicular to the area vector. The flux on the left side of the box is (80)(.002)(cos 180) = -0.16 The flux on the right side of the box is (400)(.006)(cos (inverse sine of 4/12)) = 2.26
Then net flux is -0.16 + 2.26 = 2.1
2.1 = Q / (8.85x10^-12), Q = 1.86x10^-11
I can't figure out where I went wrong with this!