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**1. Homework Statement**

The figure shows a closed Gaussian surface in the shape of a cube of edge length 3.20 m. It lies in a region where the electric field is given by E=(1.65x+2.86)i + 4.39j + 5.47k N/C, with

*x*in meters. What is the net charge contained by the cube?

**2. Homework Equations**

net flux= qenc/Eo (Gauss's Law)

Net flux= Ecos(theta)A

A= r^2

**3. The Attempt at a Solution**

The top, bottom and sides don't matter because they're constant, so I should only need to look at the front and back.

For the front side I had net flux = 2.86(cos (0deg))(10.24)=29.2864

For the back side I had net flux = (1.65*3.2+2.86)(cos 180deg)(10.24) = -83.3536

So the total net flux would be -54.0672.

Multiply this number by 8.55e-12 and I got the net charge to be -4.62275e-10. Any help would be appreciated.