How Much Does a Baseball Drop When Thrown Horizontally at 46.8 m/s Over 15.7 m?

[triplel777]

Homework Statement

A major-league pitcher can throw a baseball in excess of 46.8 m/s. If a ball is thrown horizontally at this speed, how much will it drop by the time it reaches the catcher who is 15.7 m away from the point of release?

Homework Equations

The Attempt at a Solution

i first found time using v=d/t
so 46.8 = 15.7/ t
t= 0.33

then i used the formula x=x_0 +v_0*t
so x=15.7+46.8*0.33
x= 31.14

 

[Anden]

You have the time, but you use the wrong distance formula. Remember that gravity is constantly accelerating the ball downwards.

 

[triplel777]

ok y=y_0 + v_0*t-g/2*t^2
y=0+46.8*0.33-g/2*t^2
y=15.98