How Much Does a Car Rise on a Hydraulic Lift?

Calculuslover9
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Homework Statement


A hydraulic car lift has a reservoir of fluid connected to two cylindrical fluid filled pipes. The pipe directly below the car has a diameter of 1.8 m. the pipe o which the plunger acts has a diameter of 0.045m. the plunger is depressed a distance of 1.5m. How much does the car rise?
http://tinypic.com/r/wam5xd/5
If image won't show please look at link
http://tinypic.com/r/wam5xd/5

Homework Equations



Ain X ΔXin=Aout X Δout

The Attempt at a Solution


Since the piston movess downaward thorugh a displacement Δx1 equals the volume of liquid pushed up on the right as the right piston moves upward through a displacementhttp://tinypic.com/r/2pr8wvt/5

If the image did not show please look at below or look at link

http://tinypic.com/r/2pr8wvt/5

(π (〖0.0225〗^2 m)/4m)(1.5m)=(π (〖0.9〗^2 m)/1.5m)(x)
x=0.00094m

My attempt was wrong. But I am not sure why, any hints to what I can do?
 
Last edited:
on Phys.org
The work done by Force F1 should be the same as the work done by the force F2 such that

F1x1 = F2x2

From this you can find the ratio of F2/F1 and thus get x2
 
I understand your thought processes, however, no mass is given so how, can I use that equation?
 
rock.freak667 said:
The work done by Force F1 should be the same as the work done by the force F2 such that

F1x1 = F2x2

From this you can find the ratio of F2/F1 and thus get x2

I understand your thought processes, however, no mass is given so how, can I use that equation?
 
The change in volume of fluid in one piston is equal to the change in volume of the other.
 

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