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## Homework Statement

A hydraulic lift is used to jack a 970 kg car .12m off the floor. The diameter of the output piston is .18 m, and the input force is 270 N.

If the input piston moves .13 m in each stroke, how high does the car move up for each stroke?

**2-3. Relevant equations and attempt at solving**

F

_{in}=F

_{out}

That becomes pghA=pghA

p = density

g=gravity

h=height

A=area

So I get 270=p(9.8)(.13)(A) which is the input force.

I could set that equal to the output force:

270=p(9.8)(.13)(A

_{1})=

**(p)(9.8)(h**

_{2})(.02545).02545 is the area of a circle when I plug in .09 for radius.

The p's would cancel, and I'm left with the variables A

_{1}and h

_{2}.

I know I can use the system of equations to solve this, but I want to know if I set up the equations correctly. And also, what do I do with the .12 m (that the car is lifted off the ground)??

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