How much energy is required to produce the electron-positron pair

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Homework Help Overview

The discussion revolves around calculating the energy required to produce an electron-positron pair in the field of a nucleus with atomic number Z=20, specifically considering the energy of an electron captured in the ground 1s state.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the energy of the captured electron and question how to determine the energy of the positron. There is a consideration of energy and momentum conservation in relation to the energies of the electron and positron.

Discussion Status

Some participants have provided insights into the relationship between the energies of the electron and positron, suggesting that they may be equal. There is an ongoing exploration of the implications of the nuclear field on the energy required for pair creation.

Contextual Notes

There is a noted confusion regarding the phrase "in the filed of nucleus," with participants questioning its relevance to the problem. The original poster has acknowledged a typographical error in the term used.

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Homework Statement


How much energy is required to produce the electron-positron pair in the filed of nucleus (Z=20) if electron is captured to the ground 1s state of the system.

The Attempt at a Solution



I can calculate the energy of the captured electron from

E = - εZ2/(2n2) where ε=me4/hbar2≈27.2eV

E = - 5442eV

Now I have to add this energy to the energy of created positron to have total required energy, right ? But I do not know how to find energy of a positron.
 
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hi vst9! :smile:
vst98 said:
… But I do not know how to find energy of a positron.

won't it be the same as the energy of the electron?
 
hi tiny-tim !

Yes I think so, then it is the energy and momentum conservation that places a restriction
on the positron to have the same energy as electron , right ?

I was a little bit confused by the "... in the filed of nucleus" part of the question, then
this filed of a nucleus does not change much (except maybe the needed energy).

So, the needed energy for pair creation is E=2*5442=10.88keV
 
hi vst98! :wink:

right! :smile:

i'm not sure why they mentioned the field (not "filed" :wink:) … it doesn't seem to add anything to the rest of the question :confused:
 
Ok, thanks !

(yes it is "field" and not "filed" in the original question, my flip error :) )
 

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