How much energy is stored by C2?

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SUMMARY

The energy stored by capacitor C2, which has a capacitance of 24 µF and is connected in a circuit with other capacitors, can be calculated using the formula Ucap = (1/2)CΔV². Given a voltage (V) of 20 V, the energy stored in C2 is Ucap = (1/2) * 24 µF * (20 V)². The total capacitance must be determined by analyzing the configuration of the capacitors, as some are in series and others in parallel, affecting the overall capacitance and energy calculations.

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Homework Statement


In the figure (link below), C1 = 20 [itex]\mu[/itex]F, C2 = 24 [itex]\mu[/itex]F, C3 = 16 [itex]\mu[/itex]F, C4 = 20 [itex]\mu[/itex]F, C5 = 22 [itex]\mu[/itex]F, and V = 20 V. How much energy is stored by C2?

Here's the figure:
PCGDr.png


Homework Equations


Q = C[itex]\Delta[/itex]V
Ucap = (1/2)C[itex]\Delta[/itex]V2
Ceq = C1 + C2 + C3 + ...

The Attempt at a Solution


This was a last problem on a test that I got destroyed on, and we're getting credit for corrections but I'm still clueless to where I start. Any help is appreciated!
 
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Some capacitors are connected in parallel, others in series. Determine the resultant of the capacitors C1, C2, C3, C4.

ehild
 

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