How Much Force Compresses a Spring Between Two Crates on a Frictionless Surface?

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Homework Help Overview

The problem involves two crates connected by a spring on a frictionless surface, with a focus on determining the applied force when the spring is compressed. The subject area includes mechanics and spring dynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the forces acting on the smaller mass and the acceleration of both masses. There are attempts to relate the applied force to the spring's restoring force and the overall system's acceleration.

Discussion Status

Some participants have provided guidance on how to approach the problem by considering the forces acting on the smaller mass and the relationship between acceleration and applied force. Multiple interpretations of the equations and relationships involved are being explored.

Contextual Notes

There is a mention of the spring constant and the compression distance, which are critical to the discussion. The problem setup assumes a frictionless environment and involves specific mass values for the crates.

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Two large crates, with masses 640 kg and 490 kg, are connected by a stiff, massless spring(k= 8.1 kN/m) and propelled along an essentially frictionless, level factory floor by a force applied horizontally to the more massive crate. If the spring compresses 5.1 cm from its equilibrium length, what is the applied force?
 
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What force does the spring exert? What forces act on the smaller mass? What's its acceleration?
 
Determine acceleration of the two masses (Applied force/Total mass). This will be the acceleration of each mass. Consider the smaller mass alone. Force acting on it is due to the restoring force of the spring, which is equal to kx. Write equation : Force = mass x acceleration for the smaller mass (acceleration a is in terms of the applied force F). Solve for F.
 
Vijay Bhatnagar said:
Determine acceleration of the two masses (Applied force/Total mass). This will be the acceleration of each mass. Consider the smaller mass alone. Force acting on it is due to the restoring force of the spring, which is equal to kx. Write equation : Force = mass x acceleration for the smaller mass (acceleration a is in terms of the applied force F). Solve for F.

thanks man i got the answer.
 

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