How Much Force Does Sunlight Exert on Earth?

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SUMMARY

The sunlight exerts a force of approximately 2.3 x 109 N on Earth based on the intensity of 1350 W/m2 and the Earth's radius of 6.4 x 106 m. However, the correct value provided in reference materials is 5.8 x 108 N. The discussion also clarifies the distinction between average intensity (Sav) and instantaneous intensity (I) in calculations, emphasizing that average power is derived from average intensity multiplied by area (P = SavA).

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Homework Statement


The intensity of radiation reaching the Earth from the sun is 1350 W/m2. The Earth's radius is 6.4 × 106 m. How big a force does this radiation exert on the Earth (Assume it is all absorbed)

The Attempt at a Solution



F=AP=AI/c=2.3x109 N

That's my answer. Is that correct?

(The result in my material is 5.8x108 N)

And I want to ask one more question?
What is the difference between I or Sav and S in calculation?
If we say the Sun delivers about 10000 W/m2 of energy to the Earth's surface, so that is Sav, right?

Then they told me to calculate the total power.

I see a book solved by telling P=SavA and another book was Pav=SavA.

Which one was correct? Or was Pav the same as P?
Then is this one P=SA.
 
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hi machinarium! :smile:

your answer is 4 times too much …

did you square the diameter? :redface:

the precise equation is instantaneous power = instantaneous intensity times area …

and therefore average power = average intensity times area …

in AC electric circuits the difference between instantaneous power and average instantaneous is quite important, and with lasers also, but I don't see how you could measure instantaneous power or intensity for an incoherent source like sunlight, so that has to be average (so there's not much point in saying so) :wink:
 

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