How Much Force is Needed to Ground a Flying Jet?

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Discussion Overview

The discussion centers on calculating the force required to ground a flying jet, specifically a small private jet weighing approximately 6000 kg traveling at about 850 kph. Participants explore the dynamics involved in applying a force to the aircraft's nose and the implications of various factors such as torque, lift, and angle of attack.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant inquires about the necessary force to bring a jet down, noting potential complications such as the angle of force application and altitude.
  • Another participant explains that applying force to the nose will create a torque that pitches the aircraft down, countered by the pilot's or autopilot's control inputs using the elevators.
  • A participant acknowledges the relevance of wing and tail positions in determining the aircraft's response to the applied force and expresses a desire to simplify the scenario by assuming no pilot intervention.
  • There is a discussion about the angle of attack and its relationship to lift, with a participant asking how to calculate the angle at which wings cease to provide lift.
  • One reply suggests searching for terms like "induced drag" and "angle of attack" to find equations relevant to the problem, indicating that reducing lift to zero involves managing the pitch and angle of attack effectively.

Areas of Agreement / Disagreement

Participants express varying views on the dynamics of the situation, particularly regarding the role of torque and the effects of control surfaces. The discussion remains unresolved, with no consensus on the exact calculations or methods needed to determine the required force.

Contextual Notes

Participants acknowledge several assumptions, such as the stability of the aircraft and the neglect of pilot or autopilot responses. The discussion also highlights the complexity of the forces involved, including the interplay between torque, lift, and angle of attack.

brenan
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I'm not sure this is the best forum but I'm trying to work out how to do the math
for a problem -

Imagine a small private jet of weigtht about 6000kg flying at about 850kph
If a constant force was applied to the nose of the aircraft - how much force would it take
to force it down to the ground (assuming engine thrust is constant)?

I've looked at this and suspect there may be attendant problems such as the angle
of the force applied and perhaps even the altitude?

Could someone explain how to work out such a problem and any other factors that
would need to be considered please?

Thanks
 
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Since you've chosen to apply the downforce on the nose of the target aircraft, it seems that you expect to be able to force that aircraft to pitch down, ultimately causing it to fly into the ground at high speed and crash.

The engine thrust of the target aircraft is largely irrelevant in this situation. You will be applying a torque that tends to pitch the craft down. The target pilot (or autopilot) will be pulling back on the stick, using the elevators (the horizontal control surfaces on the tail) to apply a downforce on the tail, causing a countering torque that tends to pitch the craft back up.

If you knew the maximum force that the elevators could supply and if you knew the distance from the wings to the tail and from the wings to the nose then you could equate the two torques and solve for the required force on the nose.
 
Thanks jbriggs444

Yes the assumption is the craft will be forced down.
I didn't realize the wing and tail position would be so relevant. (I hadn't thought of it as a turning force
... more of a straight line vector - so thanks for pointing that out - In my head I had envisioned a
simple beam on a pivot type system - but with the forward motion and wing lift it is obviously more complex)
To keep it simple for me to start with can we assume everything is stable and fixed
(no pilot intervention or fly by wire response)
Would I be right in assuming an angle would occur whereby the wings cease to provide lift?
How could that angle be calculated?
Could you (or anyone) point me at formulas for the likely sequence of events so that
I can see what force is required to do this and begin to understand the math a little?
thanks
 
If you are after equations, you could start with Google using a search term such as "induced drag" or "angle of attack"

http://en.wikipedia.org/wiki/Lift-induced_drag; http://en.wikipedia.org/wiki/Angle_of_attack

As you force the craft's nose down the angle of attack is reduced. That means that lift is reduced. The plane starts to lose altitude. This means that the velocity vector is no longer horizontal. This tends to increase the angle of attack, thereby restoring lift.

If you want to reduce lift to zero, you have to apply enough torque so that the plane's pitch changes fast enough that the angle of attack stays constant at near-zero while the plane describes a parabolic trajectory.

http://en.wikipedia.org/wiki/Reduced_gravity_aircraft
 
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