How much force is needed to tip a box with given dimensions and weight?

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SUMMARY

The discussion centers on calculating the force required to tip a box with dimensions 400 inches in length, 10.75 inches in width, and 26.25 inches in height, containing 1500 pounds of material positioned 7 inches above the ground. The user applied the torque equation (1500 lb)(5.375 in) = (F applied)(25 in) and calculated an applied force of 322.5 lb. The conversation highlights the importance of understanding torque and its units, as well as the potential impact of increasing the box height from 26.25 inches to 27.75 inches on tipping stability.

PREREQUISITES
  • Understanding of torque and its calculation in statics.
  • Familiarity with basic physics concepts related to force and equilibrium.
  • Knowledge of unit conversions, particularly between inches and feet.
  • Experience with real-world applications of physics in engineering or design.
NEXT STEPS
  • Research the effects of height on tipping stability in boxes and other structures.
  • Learn about the principles of static equilibrium and how they apply to tipping scenarios.
  • Explore torque calculations in different units, such as ft.lb and in.lb.
  • Investigate design modifications to improve stability in similar applications.
USEFUL FOR

Engineers, physics students, and designers involved in structural stability assessments, particularly those working with large boxes or containers in industrial settings.

poyganhunter
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Homework Statement


Hello, its been a long time since I've worked with statics or dynamics in college and now find myself in the workfield trying to figure out a current problem! What I am looking for is how much force is needed to tip a box.
The box i have has dimensions of:

Length=400in, width=10.75in, Height=26.25in
The box has 1500 hundred pounds of material centered, but located 7 in from ground level

If i were to push on the box in the center(200in from end), and 25 in from ground level(near top of box), how much force would that take?

Homework Equations





The Attempt at a Solution


initially i used an equation of

(1500lb)(5.375in)=(F applied)(25in) which gave me an applied force of 322.5lb of applied force.

Does this sound correct?
 
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poyganhunter said:

Homework Statement


Hello, its been a long time since I've worked with statics or dynamics in college and now find myself in the workfield trying to figure out a current problem! What I am looking for is how much force is needed to tip a box.
The box i have has dimensions of:

Length=400in, width=10.75in, Height=26.25in
The box has 1500 hundred pounds of material centered, but located 7 in from ground level

If i were to push on the box in the center(200in from end), and 25 in from ground level(near top of box), how much force would that take?

Homework Equations





The Attempt at a Solution


initially i used an equation of

(1500lb)(5.375in)=(F applied)(25in) which gave me an applied force of 322.5lb of applied force.

Does this sound correct?

SOme weird units you are using there, but thenumbers look OK.
You are using torques, so the final units should be ft.lb or perhaps in.lb.
 
what am i missing in this equation then? if it helps to add more info the issue we are having is these boxes tipping due to people pushing near the top. what I am really looking for is how much of a difference 1.5 inches would make in the height of the box. its designed right now to be 26.25 inches high, but we are thinking about increasing the height to 27.75 to accommodate the addition of another 2x4 on the bottom for a runner. what i would like to do is a comparison of the to to show the guys how much difference there is between the two..

are there any equation i should add or would be better suited?
 

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