Box problem on work/force/energy

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SUMMARY

The discussion focuses on calculating the net work done on a 50 kg box being pulled with a force of 250 N across the ground at a constant speed of 4 m/s for 3 seconds, considering friction. The net work is determined by the net force acting on the box, while the work done by applied forces can be calculated using the formula W = Fd. The work done by friction can be derived from the net work and the applied work. Additionally, the power output of the applied force is calculated using P = W/t, and the final speed of the box without friction can be determined using kinetic energy principles.

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Homework Statement


A 50Kg box is pulled across the ground with a force of 250 N. The speed of the box is a constant 4m/s for 3 seconds. Friction is NOT 0.
a) What is the net work done on the box by all forces ?
b) How much work is done on the box by applied forces?
c) What is the work done by the friction on the box?
d) What is the power output of the applied force?
e) If there were no friction, and the force was applied for 8m, what would the resulting speed be if the box started from rest?


Homework Equations


f=ma
KE=.5mv^2
PE=mgh
P=fvcosx


The Attempt at a Solution


b) w=250d
c)w=frkd (Friction constant and distance are what I can't find)
d) p=w/3
e)

I guess what is mostly stumping me on these problems is the fact that I don't know how to find the distance or the spring constant
 
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Your answers to b and d look right. For a, remember that net work is net force times displacement, so you just have to find the net force acting on the box.

For c, you don't have to know the friction constant -- net work equals the sum of all works, in this case friction and applied. If you have net work and the applied work, then you can find the work done by friction.

For e, there's no friction, so the applied work will feed directly into the kinetic energy of the box, and from there you can find the final speed.
 
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