Box problem on work/force/energy

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In summary, a 50kg box is pulled across the ground with a force of 250N, maintaining a constant speed of 4m/s for 3 seconds. The net work done on the box by all forces can be found by multiplying the net force by the displacement. The work done by applied forces can be found by multiplying the force by the displacement. The work done by friction can be found by subtracting the applied work from the net work. The power output of the applied force can be found by dividing the work by the time. If there were no friction and the force was applied for 8m, the resulting speed of the box starting from rest can be found using the kinetic energy equation.
  • #1
brnnpink4
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Homework Statement


A 50Kg box is pulled across the ground with a force of 250 N. The speed of the box is a constant 4m/s for 3 seconds. Friction is NOT 0.
a) What is the net work done on the box by all forces ?
b) How much work is done on the box by applied forces?
c) What is the work done by the friction on the box?
d) What is the power output of the applied force?
e) If there were no friction, and the force was applied for 8m, what would the resulting speed be if the box started from rest?


Homework Equations


f=ma
KE=.5mv^2
PE=mgh
P=fvcosx


The Attempt at a Solution


b) w=250d
c)w=frkd (Friction constant and distance are what I can't find)
d) p=w/3
e)

I guess what is mostly stumping me on these problems is the fact that I don't know how to find the distance or the spring constant
 
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  • #2
Your answers to b and d look right. For a, remember that net work is net force times displacement, so you just have to find the net force acting on the box.

For c, you don't have to know the friction constant -- net work equals the sum of all works, in this case friction and applied. If you have net work and the applied work, then you can find the work done by friction.

For e, there's no friction, so the applied work will feed directly into the kinetic energy of the box, and from there you can find the final speed.
 
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1. What is the "box problem" on work/force/energy?

The "box problem" is a common physics problem that involves calculating the work, force, and energy involved in moving a box from one location to another. It typically involves a box of known mass being pushed or pulled along a flat surface with a known force, and the goal is to calculate the work done and the final energy of the box.

2. How do you calculate work, force, and energy in the box problem?

To calculate work, force, and energy in the box problem, you need to use the equations W = Fd, F = ma, and E = ½mv². W represents work, F represents force, d represents distance, m represents mass, a represents acceleration, and v represents velocity. By plugging in the known values for these variables, you can solve for the unknowns.

3. What factors affect the work, force, and energy in the box problem?

The main factors that affect work, force, and energy in the box problem are the mass of the box, the force applied to the box, and the distance the box is being moved. Other factors that may affect these values include the angle of the surface the box is being moved on, the coefficient of friction between the box and the surface, and any external forces acting on the box.

4. How does the box problem relate to real-world situations?

The box problem is a simplified version of many real-world situations, such as pushing a heavy object across the floor or lifting a weight off the ground. In these situations, the principles of work, force, and energy that are used to solve the box problem also apply.

5. Are there any limitations to the box problem on work/force/energy?

Like any simplified physics problem, the box problem has limitations and does not accurately represent all real-world situations. For example, it does not account for factors such as air resistance, which can significantly affect the work, force, and energy involved in moving an object. It is important to keep these limitations in mind when applying the concepts of work, force, and energy to real-world situations.

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