How Much Gas Must a Rocket Expel to Alter Its Course by 23 Degrees?

  • Thread starter Thread starter GreenPrint
  • Start date Start date
  • Tags Tags
    Velocity
Click For Summary
SUMMARY

The discussion focuses on calculating the mass of gas a 4200-kg rocket must expel to alter its course by 23 degrees while traveling at 120 m/s. The expelled gas has a velocity of 2200 m/s relative to the rocket. The correct mass of gas to be expelled is determined to be 95 kg. The key equation used is the conservation of momentum, specifically m1 V1 = (m1 + mg) Vy, where Vy is the new velocity in the y-direction after the gas expulsion.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Basic trigonometry for calculating velocity components
  • Familiarity with rocket propulsion concepts
  • Ability to set up and solve algebraic equations
NEXT STEPS
  • Study the conservation of momentum in multi-body systems
  • Learn about rocket propulsion and thrust equations
  • Explore the application of trigonometric functions in physics problems
  • Review algebraic manipulation techniques for solving equations
USEFUL FOR

Students preparing for physics exams, particularly those focusing on mechanics and rocket propulsion, as well as educators looking for practical examples of momentum conservation in action.

GreenPrint
Messages
1,186
Reaction score
0

Homework Statement



A 4200-kg rocket is traveling in outer space with a velocity of 120m/s toward the Sun. It needs to alter its course by 23 degrees, which can be done by shooting is rockets briefly in a direction perpendicular to it’s original motion. If the rocket gases are expelled at a speed of 2200 m/s relative to the rocket, what mass of gas must be expelled?

Homework Equations



momentum = mass x velocity

The Attempt at a Solution



Ok so I'm reviewing for my midterm and I don't remeber how to do this problem

I know I need to calculate the new velocity. That is easy.

Vy = 120 m/s tan 23 = 50.94 m/s

Now supposively the answer is 95 kg.
I can't seem to get this answer for the life of me. I set up a quation like this

m1 V1 = (m1 + mg )Vy

I keep on getting the wrong answer how do i do this. I think i need help setting up the equation becasue I think I'm reading this problem wrong or soemthing here
 
Physics news on Phys.org


Momentum in the "y" direction should be the same before and after. Before, the rocket has no velocity in the y direction, so its momentum in that direction is zero (I suspect you already get this part)

After the rocket burn, you essentially have two objects: the rocket and a mass of gas. Adding the momenta of these in the y direction should give you zero, but keep in mind that the rocket's mass is not the same because it lost some mass of gas. Can you write an equation for this?
 

Similar threads

Replies
1
Views
7K
Replies
20
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
Replies
4
Views
6K