Calculating Block Rise & Rocket Course Change: Help Needed!

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SUMMARY

The discussion focuses on two physics problems involving momentum and energy conservation. The first problem calculates the height a 1.4 kg block of wood will rise after a 21 g bullet, traveling at 310 m/s, becomes embedded in it. The second problem involves a 3700 kg rocket altering its course by 35 degrees by expelling mass at a speed of 1900 m/s. Participants emphasize the importance of applying kinematic equations and energy balance equations to solve these problems effectively.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with kinematic equations of motion
  • Knowledge of energy conservation in inelastic collisions
  • Basic rocket propulsion concepts
NEXT STEPS
  • Study the conservation of momentum in inelastic collisions
  • Learn how to apply kinematic equations to projectile motion
  • Research energy balance equations in mechanical systems
  • Explore rocket propulsion and mass expulsion calculations
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Students in physics, aerospace engineers, and anyone interested in solving problems related to momentum and energy in mechanical systems.

Elvis
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Please help me .

(1)- A gun is fired vertically into a 1.4 kg block of wood at rest directly above it. If the bullet has a mass of 21 g and a speed of 310 m/s, how high will the block rise into the air after the bullet becomes imbeded in it ?

(2)- A rocket of total mass 3700 kg is traveling in outer space with a velocity of 110 m/s toward the Sun. It wishes to alter its course by 35 degrees, and can do this by firing its rocket briefly in a direction perpendicular to its original motion. If the rocket gases are expelled at a speed of 1900 m/s, how much mass must be expelled ?
 
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Elvis, you must show your own work and attempt at a solution before we can help you with homework/coursework problems (see the "Rules" link at the top of the page).

What are the kinematic equations of motion that you will use to solve these problems? What energy balance equations can also be of help?
 

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