How Much Heat Is Involved if 927 Grams of Mg(OH)2 Reacts?

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SUMMARY

The reaction of 927 grams of Mg(OH)2 with phosphoric acid (H3PO4) releases 70,482 kJ of heat. This calculation is based on the stoichiometry of the reaction, where 3 moles of Mg(OH)2 yield 1427 kJ of energy. The conversion from grams to moles utilizes the molar mass of Mg(OH)2, which is 56.305 g/mol. The heat release is directly proportional to the amount of Mg(OH)2 reacted, confirming the calculations provided in the discussion.

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davie08
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Homework Statement


given:

2 H3PO4 + 3 Mg(OH)2 + 1427 kj → 6 H20 + Mg3(PO4)2

How much heat is involved if 927 grams of Mg(OH)2 reacts?


Homework Equations





The Attempt at a Solution



927 g x Mg(OH)2 mole/56.305g x 1427 kj/3Mg(OH)2 mole = 70,482 kj


I just felt like I did this wrong. Also how do I make the numbers small for showing the number of each element?
 
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No idea where 1427 kj/3Mg(OH)2 mole came from - you have not listed it in the problem. It doesn't have to be wrong, it is just not clear if it is OK.

[noparse]H3O+[/noparse] renders as H3O+.
 

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