Calculating Heat Needed to Raise Water Temperature from 8.2◦C to 73◦C

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SUMMARY

The discussion focuses on calculating the heat required to raise the temperature of 62 grams of water from 8.2°C to 73°C using the formula Q=mcΔT. The specific heat of water is confirmed as 4180 J/kg·°C. The calculated heat needed is 16,793.568 J, which can be rounded to 17 kJ or 16.8 kJ for practical purposes. The solution is verified as correct, with the final answer accepted as 16,794 J.

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Homework Statement



This is for my physics homework and I haven't done gen chem in a while so I was wondering if this was right:

You need to raise the temperature of 62 g of water from 8.2◦C to 73◦C. How much heat is needed to accomplish this? The specific heat of water is 4180 J/kg ·◦C. Answer in units of J.

Homework Equations



Q=mc\DeltaT

The Attempt at a Solution



Q=(0.062 kg)(4180 J/kg◦C)(73◦C-8.2◦C) = 16,793.568 J

Is that right? TIA
 
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Correct approach, again problem with SD. Answering 17 kJ, or 16.8 kJ will do.
 
Thank you! I put in 16,794 and it was right.
 

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