How Much Heat is Released When Water Cools?

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SUMMARY

The discussion centers on calculating the heat released when 25 grams of water cools from 77 degrees Celsius to 50 degrees Celsius using the equation Q = cmΔT. The specific heat capacity of water is established as 1 cal/g°C, and the temperature change (ΔT) is determined to be 27 degrees Celsius. The total heat released is calculated to be 675 calories, derived from the equation Q = (25 g)(1 cal/g°C)(27°C).

PREREQUISITES
  • Understanding of specific heat capacity
  • Familiarity with the equation Q = cmΔT
  • Basic knowledge of temperature scales
  • Ability to perform unit conversions (calories to joules)
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  • Study the concept of specific heat capacity in different materials
  • Learn about calorimetry and its applications
  • Explore the relationship between heat transfer and temperature changes
  • Investigate the conversion between calories and joules for energy calculations
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Students studying thermodynamics, educators teaching energy transfer concepts, and anyone interested in understanding heat calculations in physical science.

noorjabaieh
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Need help on energy equations please!

Homework Statement


I need help on this homework question please i don't know how to solve it


Homework Equations


how many calories of heat are released by 25 g of water as it drops in temperature from 77 degrees c to 50 degrees c ( 1 cal= 4.18)


The Attempt at a Solution



I don't know which equation i should use
Q= cmDeltaT ?
 
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try it.
 

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