What is the specific heat of the metal in this specific heat problem?

Click For Summary
SUMMARY

The specific heat of the metal in the given problem can be calculated using the principle of conservation of energy, where the heat lost by the metal equals the heat gained by the water. The formula used is qrxn = -qwater, leading to the equation 12C(90 - 25) = -25(25 - 22.5)(4.184). The temperature of the water reaches 25.0 °C, indicating thermal equilibrium, which confirms that the final temperature of the metal is also 25.0 °C.

PREREQUISITES
  • Understanding of specific heat capacity
  • Knowledge of heat transfer principles
  • Familiarity with the formula q = mcΔT
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of thermal equilibrium in heat transfer
  • Learn about calorimetry and its applications
  • Explore specific heat calculations for different materials
  • Investigate the effects of mass and temperature change on heat transfer
USEFUL FOR

Students in chemistry or physics, educators teaching thermodynamics, and anyone interested in understanding heat transfer and specific heat calculations.

lc99
Messages
161
Reaction score
3

Homework Statement



A 12.0 g sample of a metal is heated to 90.0 °C. It is then dropped into 25.0 g of water. The temperature of the water rises from 22.5 to 25.0 °C. The specific heat of water is 4.18 Jg-1°C-1.
Calculate the specific heat of the metal. Express your answer in Jg-1°C-1

Homework Equations

The Attempt at a Solution



Why is the change in temperature for the metal 90 - 25? Why is 25 degrees celsius the initial temp?[/B]
 
Physics news on Phys.org
Is that an attempt at solution ?
Who says the initial temp is 25 C ?
 
BvU said:
Is that an attempt at solution ?
Who says the initial temp is 25 C ?
The solution goes like this.qrxn=-qwater
mcdeltat= -mcdeltat
12C(90-25)=-25(25-22.5)(4.184) and solve for C
 
lc99 said:
Why is the change in temperature for the metal 90 - 25? Why is 25 degrees celsius the initial temp?
If the temperature of the water raises up to 25.0 °C and not more, it means that it is the point where there is thermal equilibrium. The metal must be at the same temperature.
 

Similar threads

Replies
54
Views
9K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 21 ·
Replies
21
Views
2K