How Much Hydrogen Gas Is Produced in a Magnesium and Hydrochloric Acid Reaction?

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SUMMARY

The reaction between 3.50 g of magnesium metal and 100 mL of 2.00 M hydrochloric acid produces hydrogen gas (H2) and magnesium chloride (MgCl2). The balanced chemical equation is 2Mg + 2HCl → 2MgCl2 + H2. The limiting reactant is magnesium, yielding 0.072 moles of H2, which corresponds to a volume of 1.61 liters at standard conditions (0.00°C and 1.00 atm). The correct answer for the volume of hydrogen gas produced is 2.24 liters, indicating an error in the initial calculation.

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Homework Statement


3.50 g of magnesium metal is added to 100. mL of 2.00 M aqueous hydrochloric acid. The substances react to completion, producing aqueous magnesium chloride and hydrogen gas (H2). How many liters of pure hydrogen gas, measured at 0.00oC and 1.00 atm are produced in this reaction?

Homework Equations


PV=nRT

The Attempt at a Solution


Rxn Eq: 2Mg + 2HCl --> 2MgCl + H2

3.5 g Mg x (1 mol/24.3g) = .144 mol Mg
2 mol/L HCl x .1L = .2 mol HCl
Mg is limiting reactant

.144 mol Mg x (1 mol H2/2 mol Mg) = .072 mol H2

V=(nRT)/P=[(.072)(.08206)(273)] / 1 = 1.61 L H2

It says the answer is 2.24L?
 
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What is formula of magnesium chloride?

Hint: which periodic table group?

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WOW! I can't believe I missed that. I always miss these on minor mistakes that don't even have to do with the difficult part... Thanks
 

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