Zinc metal is added to hydrochloric acid to generate.......

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Discussion Overview

The discussion revolves around the calculation of the number of moles of hydrogen gas generated when zinc metal is added to hydrochloric acid. The scenario involves determining the moles based on given pressures and volume, with a focus on the application of the ideal gas law and the concept of partial pressures.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a homework statement involving the reaction of zinc with hydrochloric acid and the collection of hydrogen gas over water, noting the total pressure and volume of the gas mixture.
  • Another participant suggests that the total pressure is the sum of the partial pressures of the liquid and hydrogen, converting the vapor pressure of water from torr to atm.
  • A subsequent reply reiterates the assumption about total pressure and provides calculations for the pressure of hydrogen gas based on the total pressure and vapor pressure of water.
  • One participant applies the ideal gas law (PV=nRT) to arrive at a specific answer for the number of moles of hydrogen gas, stating it as 0.0681 mol.
  • Another participant reflects on the relationship between volume and moles of gas, mentioning atmospheric pressure and the concept of gas volume at standard temperature and pressure (STP), while expressing uncertainty about the unit "torr" and its historical context.

Areas of Agreement / Disagreement

There is no consensus on the final answer, as participants provide different interpretations and calculations regarding the number of moles of hydrogen gas. Multiple competing views remain regarding the correct approach and final value.

Contextual Notes

Participants express uncertainty about the interpretation of the problem, particularly regarding the pressure of the liquid and the relevance of temperature. There are also unresolved steps in the calculations leading to the determination of moles.

AMan24
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Please don't ignore the template.

Homework Statement


Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the same as that of pure water at 20.0°C (18 torr). The volume of the mixture is 1.7 L, and its total pressure is 0.987 atm. Determine the number of moles of hydrogen gas present in the sample.

a.
0.272 mol

b.
0.04 mol

c.
0.997 mol

d.
0.139 mol

e.
0.0681 mol

So there's some container with a volume of 1.7L and pressure of 0.987... The amount of hydrogen and the other substance in the container are unknown. We also know that the other substance has the same pressure as water does at 20C, (i don't think we use the temperature to find the solution)... And we know the pressure of the other substance is 18torr.

Note; I'm not sure if the question is saying the pressure of water/the substance at 20C is 18torr. Or if the temperature of the substance is the same as water when the substance is 20C.
 
Last edited:
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Assume total pressure is the sum of partial pressure of the liquid and hydrogen.
 
Borek said:
Assume total pressure is the sum of partial pressure of the liquid and hydrogen.

So convert 18 torr to atm = 0.0236 atm.
P total = P1 + P2...
0.987atm = 0.0236atm + P2...
P2=0.9634.

So now i know the pressure of the hydrogen. The unknowns are the volume of the other substance and the hydrogen. Thanks for the help with this step!
 
Ok so now its PV=nRT and the answer is 0.0681 mol
 
I got it, you can get it, fairly fast thinking:

that's essentially atmospheric pressure and one of the several physical numbers it is useful to remember (was dinned into us at school) is 1 mole gas is 22.4 L (at stp). Water vapour pressure? - negligible by comparison. Thinks of inverted full test tube, you leave it for a time, get a quite small bubble at top, showing this quite small. (Right thinking? :olduhh: ) . Still don't actually remember what a torr is, look up, ah we used to call that 1 mm of mercury. But remember, also from school barometer. 1 arm = 760 mm Hg. So verified neglible for this purpose.

So 1.7 L is 1.7/22.4 mole, awkward. But it's somewhat less than a tenth. b is quite a lot less, all the others are more, e looks right.

(Wasn't such a bad school if I can hack that at this distance.).
 

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