How Much Information Can Nods and Shakes Convey in a Bridge Game?

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    Entropy Shannon entropy
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Discussion Overview

The discussion revolves around the amount of information that can be conveyed through nods and shakes in a bridge game, specifically focusing on the Shannon entropy associated with transmitting 13 cards from a deck of 52. The scope includes theoretical considerations of information theory and combinatorial arrangements.

Discussion Character

  • Technical explanation, Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant calculates that specifying a single card requires approximately 6 bits, leading to a total of 13 times that for 13 independent cards.
  • Another participant notes that the question suggests an answer of 40 bits and seeks a coding function with an entropy of 50, indicating a potential misunderstanding of the question's requirements.
  • A later reply clarifies that the question may be asking for the information needed to transmit an arrangement of 13 cards collectively, rather than individually, leading to a calculation involving combinations, resulting in an entropy of approximately 39.21 bits.

Areas of Agreement / Disagreement

Participants express differing interpretations of the question, with some focusing on individual card specification and others on the collective arrangement of cards. No consensus is reached regarding the correct approach to the problem.

Contextual Notes

There are unresolved assumptions regarding the interpretation of the question and the nature of the coding function required. The dependence on definitions of entropy and arrangements is also noted.

szpengchao
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consider a pack of 52 cards in a bridge game. a player try to convey 13 cards by nods of head or shake of heads to his partner. find the shannon entropy
 
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You need [itex]\rm{log}_{2}52 \approx 6 bits/card[/itex] to specify a single card (admitting that they are all equiprobable). For 13 independent cards, you'll need [itex]13\times\rm{log}_{2}52 bits[/itex].
 
JSuarez said:
You need [itex]\rm{log}_{2}52 \approx 6 bits/card[/itex] to specify a single card (admitting that they are all equiprobable). For 13 independent cards, you'll need [itex]13\times\rm{log}_{2}52 bits[/itex].

but the question tells the answer is 40, and it asks to find a coding function with entropy 50
 
Well, then the question is asking for the amount of information necessary to transmit an arrangement of 13 cards as a whole and not individually; that was not clear from the question.

There are [itex]\binom{52}{13}[/itex] possible arrangements, and this gives an entropy of [itex]-\rm{log_2}\binom{52}{13} \approx 39.21 bits[/itex].
 

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