How much magnesium is needed to react with oxygen gas at specified conditions?

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SUMMARY

To determine the mass of magnesium required to react with oxygen gas in a 0.25 L container at 80°C and 770 mmHg, one must apply stoichiometry and the ideal gas law (PV=nRT). The reaction produces magnesium oxide (MgO) from magnesium (Mg) and oxygen (O2). The possible mass solutions presented are 0.945 g, 0.418 g, and 0.124 g, indicating a need for further calculations to identify the correct answer based on the stoichiometric coefficients and the ideal gas law results.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Familiarity with the ideal gas law (PV=nRT)
  • Knowledge of the reaction between magnesium and oxygen
  • Basic skills in unit conversion and mass calculations
NEXT STEPS
  • Calculate the amount of oxygen gas using the ideal gas law (PV=nRT)
  • Determine the stoichiometric coefficients for the reaction between magnesium and oxygen
  • Convert the moles of oxygen to grams of magnesium required for the reaction
  • Verify calculations with multiple methods to confirm the correct mass of magnesium
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical reactions and stoichiometry, particularly those working with magnesium and oxygen reactions.

bluegirlbalance
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Magnesium burns in oxygen gas to produce magnesium oxide. What mass of magnesium will react with a 0.25 L container of oxygen gas at 80oC and 770 mmHg? :confused:



I need to use stoichiometry to set up the pronlem and PV=nRT to solve.

I have three possible solutions, but I don't know which one is the correct one. The solutions I have are .945 g, .418 g, and .124 g.
 
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Have you done any work on this problem? If you show work we can help you through the problem. Do you have the equation of the reaction?
 
Use PV=nRT to calculate amount of oxygen.
 

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