How much oxygen escaped from the container?

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Homework Help Overview

The problem involves calculating the mass of oxygen in a container under varying pressure and temperature conditions. The initial state has a manometric pressure of 4 atm and a temperature of 470°C, while the final state shows a pressure drop to 3.5 atm and a temperature of 270°C.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the use of the ideal gas law and the significance of using absolute pressure versus gauge pressure. There are questions regarding the initial calculations and the correct molar mass of oxygen.

Discussion Status

Some participants have provided alternative calculations based on different interpretations of pressure measurements. There is an ongoing exploration of the definitions of manometric pressure and gauge pressure, with some guidance offered on the correct approach to the problem.

Contextual Notes

Participants note the importance of using absolute pressures in calculations and clarify the distinction between atomic mass and molar mass in the context of oxygen. There is also mention of potential confusion regarding terminology related to pressure measurements.

Karol
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Homework Statement


Into a 56[liter] container oxigen is filled in with manometric pressure of 4[atm] and temp' 470C. what is the mass.
Then a leak happens and the pressure drops to 3.5[atm] and temp' 270C.
How much oxigen escaped.

Homework Equations


$$PV=nRT$$
$$R\left[\frac{liter\cdot atm'}{mole\cdot ^0K}\right]=0.08208$$
Atomic number O2=16

The Attempt at a Solution


The initial conditions: ##3[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=6.4[mole]##
$$m=6.4\cdot 16=102.3[gr]$$
Second stage:
$$\frac{P_1V_1}{n_1T_1}=\frac{P_2V_2}{n_2T_2}\rightarrow\frac{P_1V_1}{m_1T_1}=\frac{P_2V_2}{m_2T_2}$$
Our volume is fixed, so: ##\frac{3}{102.3\cdot 320}=\frac{2.5}{m_2\cdot 300}\rightarrow m_2=90.97[gr]##
Is it correct?
 
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Karol said:

Homework Statement


Into a 56[liter] container oxigen is filled in with manometric pressure of 4[atm] and temp' 470C. what is the mass.
Then a leak happens and the pressure drops to 3.5[atm] and temp' 270C.
How much oxigen escaped.

Homework Equations


$$PV=nRT$$
$$R\left[\frac{liter\cdot atm'}{mole\cdot ^0K}\right]=0.08208$$
Atomic number O2=16

The Attempt at a Solution


The initial conditions: ##3[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=6.4[mole]##
$$m=6.4\cdot 16=102.3[gr]$$

Why did you calculate with 3 atm?
And the oxygen gas consists of O2 molecules. The atomic mass of oxygen is 16 g, but you have to work with the molar mass.
 
manometric pressure is the pressure above atmospheric, right? so i have to take absolute pressures, it's then 5 atm.
And the molar mass is 32[gr]
$$5[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=10.7[mole]$$
$$m=10.7\cdot 32=341.1[gr]$$
 
Karol said:
manometric pressure is the pressure above atmospheric, right? so i have to take absolute pressures, it's then 5 atm.
And the molar mass is 32[gr]
$$5[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=10.7[mole]$$
$$m=10.7\cdot 32=341.1[gr]$$

I know pressure above atmospheric as "gauge pressure". You have to know what manometric pressure is. I never heard that.
 
Yes, it's gauge pressure
 

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