How much power does my car actually need to maintain speed?

In summary, the conversation discussed the power requirements for a car traveling at a constant speed and the factors that contribute to it, such as rolling friction, air drag, and external forces like gravity. It also touched on the losses in ICE/mechanical systems and the potential for recovering waste heat in hybrid setups. Overall, it was mentioned that most passenger cars only need about 20 hp to overcome rolling friction and air drag, and that there have been attempts to recover waste heat in car engines but with limited success.
  • #1
Schtoogie
9
0
Hello PF, I have a problem that I cannot solve.

Assuming my car weighs 4000 pounds with passengers and cargo and is traveling at 100 feet per second, this requires 4000lb*100ft/s = 400,000 ft-lb/s or 727.3 hp of work. But I know the engine is only producing about 50 or 60 hp, and I'm maintaining speed! So... what gives? What am I missing?

Thank you so much for your help!
 
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  • #2
Why does it need 4000 lb force? That would only be true if it were moving vertically and pulling against gravity.

Moving horizontally it needs force to accelerate from rest to 100 ft/sec , but then continues at that speed unless acted on by an external force. The external forces which act in the direction of motion are friction (and air resistance).
Gravity is acting perpendicular to the direction of motion, so it does not affect speed in the horizontal direction.

You only need force to overcome gravity when you go up hill.
 
  • #3
So to calculate power required I would need to find engine torque at the wheel and then divide out wheel radius, right? And subtract from that the force of drag and friction?
 
  • #4
Schtoogie said:
So to calculate power required I would need to find engine torque at the wheel and then divide out wheel radius, right? And subtract from that the force of drag and friction?
You could do that, but probably get a headache.

When traveling on level roads at constant speed, most passenger cars need only about 20 hp or so to overcome rolling friction and air drag. (More power would be needed, obviously, if you were carrying a door on top of your car, with the flat side perpendicular to the line of travel.

The power required to overcome rolling friction is pretty constant regardless of vehicle speed, but the force produced by air drag is proportional to the square of the speed of the car. So, there is 4 times as much air drag created at 60 mph as there is created at 30 mph.

All of that extra power capability in a car's engine is put there to drive things like the alternator, power steering, auto trans, etc. and to allow one to accelerate from standing still to cruising speed without taking all day.

The following article discusses some basic power requirement calculations for cars:

http://wps.aw.com/wps/media/objects/877/898586/topics/topic02.pdf
 
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  • #5
I think your first approach was the simplest. If you know the force opposing the car, then multiply it by the speed and there you have the power, irrespective of how it is transmitted through the drive train and wheels. You would have to allow for some wasted power in the dive train, but what matters to you may be the power available at the wheels rather than at the engine.

Your problem is in estimating the frictional forces. You may get some data if you have a long even slope and measure the steady state rolling speed: at that speed the frictional drag equals the gravitational pull along the slope (g cos(slope) )
Maybe you could also get some data from plotting a speed/time graph rolling to a stop on various slopes, but I've not done this, so I'm not sure what the maths would be like.

Edit - PS SteamKing looks more useful than my comments. A helpful link.
 
  • #6
Thanks, that is a great link. It's amazing how many losses there are in ICE/mechanical systems! If someone could capture that waste heat and send it to an electric motor in a hybrid setup, that would improve economy tremendously.
 
  • #7
SteamKing said:
When traveling on level roads at constant speed, most passenger cars need only about 20 hp or so to overcome rolling friction and air drag. (More power would be needed, obviously, if you were carrying a door on top of your car, with the flat side perpendicular to the line of travel.
That's a good estimate.

I've done the calculation before, using the energy in gasoline and an efficiency of 30% or so. 30 mpg at 60 mph is 2 gal/hr, and works out to about 17 hp. So 20 hp is a good value for a car getting perhaps 25 mpg, which is closer to average.
Merlin3189 said:
I think your first approach was the simplest. If you know the force opposing the car...
Easiest to calculate perhaps, but finding that force is very difficult.
 
  • #8
Schtoogie said:
Thanks, that is a great link. It's amazing how many losses there are in ICE/mechanical systems! If someone could capture that waste heat and send it to an electric motor in a hybrid setup, that would improve economy tremendously.
About 65% of the energy is wasted as heat. Several car companies have experimented with recovering it. Here's an example:
http://en.wikipedia.org/wiki/Turbosteamer
In short, it is only a 15% gain in fuel efficiency which is a bit disappointing. It says it recovers 80% of the waste heat -- but then it runs that through a steam engine and only turns 35% of that into useful work.
 
  • #9
Interesting device and research. Cool to know that 80% of the heat was captured. Now industry could really benefit from a turbine that can condense working fluids as part of the thermal cycle. So much energy is wasted on running condensers and pumps to move still-hot, energy-dense steam.
 

1. What factors affect the amount of power needed to maintain speed in a car?

The amount of power needed to maintain speed in a car is affected by several factors, including the weight of the car, the aerodynamics of the car, the road conditions, and the mechanical efficiency of the engine and transmission.

2. Does the type of fuel used in a car affect the power needed to maintain speed?

Yes, the type of fuel used in a car can affect the amount of power needed to maintain speed. For example, diesel engines typically have more torque, which can require less power to maintain speed compared to gasoline engines.

3. How does the speed of the car impact the amount of power needed?

The speed of the car is directly proportional to the power needed to maintain it. This means that as the car goes faster, more power is needed to overcome air resistance and maintain the speed.

4. Can the terrain or elevation of the road affect the power needed to maintain speed?

Yes, the terrain and elevation of the road can have a significant impact on the power needed to maintain speed. Uphill roads or roads with rough terrain will require more power to maintain speed compared to flat and smooth roads.

5. How can I calculate the power needed for my specific car to maintain a certain speed?

The power needed to maintain a certain speed can be calculated using the formula P = F x v, where P is power in watts, F is the force needed to overcome resistance (such as air resistance and road resistance), and v is the velocity or speed of the car in meters per second. This calculation may vary depending on the specific characteristics of your car and road conditions.

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