How Much Proper Time Does an Observer Measure Falling Into a Black Hole?

Click For Summary

Homework Help Overview

The problem involves an observer falling radially toward a black hole with a mass of 3 solar masses, seeking to determine the proper time measured by the observer as they travel between two specified radii, 6GM/c² and the event horizon. The context is rooted in general relativity, specifically utilizing the Schwarzschild solution.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conservation of energy and momentum in the context of the problem, questioning how to express kinetic and potential energies. There is an exploration of the proper time increment and the relationship between proper time and radial distance, with a focus on deriving an expression for dr/dτ.

Discussion Status

The discussion is ongoing, with participants raising questions about conserved quantities and the implications of the observer's 4-velocity in Schwarzschild space-time. There is a productive exploration of the problem's requirements and the relationships between different physical quantities.

Contextual Notes

Participants note the challenge of expressing energy in the context of the problem and the implications of the observer's radial fall, indicating a need for further clarification on these concepts.

rrfergus
Messages
4
Reaction score
0

Homework Statement


An observer falls radially inward toward a black hole of mass M, which is equal to 3 solar masses, starting with zero kinetic energy at infinity. How much time is measured by this observer as he travels between radii r1 = 6GM/c2 and the event horizon?


Homework Equations


The only solution to Einstein's equations we have learned is the Schwarzschild radius, so the solution probably involves that (I'm guessing). The Schwarzschild solution is
ds2 = -c22(1 - 2GM/rc2)dt2 + dr2/(1 - 2GM/rc2) + r2(dθ2 + sin2θdσ2) in spherical coordinates.


The Attempt at a Solution


I'll be honest, I really have no idea where to even start with this problem
 
Physics news on Phys.org
What conserved quantities do we have at our disposal?
 
Energy should be conserved. Momentum also, but I think energy conservation would be more relevant to the problem. I just don't know how to express the kinetic or potential energies in this context, or to calculate the time.
 
rrfergus said:
Energy should be conserved. Momentum also, but I think energy conservation would be more relevant to the problem. I just don't know how to express the kinetic or potential energies in this context, or to calculate the time.
What do you know about the energy-momentum tensor, in the context of GR?
 
rrfergus said:
Energy should be conserved. Momentum also, but I think energy conservation would be more relevant to the problem. I just don't know how to express the kinetic or potential energies in this context, or to calculate the time.

Let's think about this from a top down point of view. What does the problem want and what does it tell us? Well it wants the proper time ##\tau## measured by the observer between two given radii ##r = 6M## and ##r = 2M## right? Well if we know how much proper time ##d\tau## is incremented when the observer travels an amount ##dr##, we can integrate between the two radii and we're done. So we want to find an expression for ##\frac{dr}{d\tau}## somehow. Conserved quantities will be key here. In this case energy is all that matters since the observer falls in radially and hence has no angular momentum.

First, what's the conserved energy in Schwarzschild space-time?

Next, what do we know about the magnitude ##u_{\mu}u^{\mu} = g_{\mu\nu}u^{\mu}u^{\mu}## of the observer's 4-velocity ##u^{\mu} = (\frac{dt}{d\tau}, \frac{dr}{d\tau}, \frac{d\theta}{d\tau}, \frac{d\phi}{d\tau})##? What is it always equal to?

Finally what can we say about ##\frac{d\theta}{d\tau}## and ##\frac{d\phi}{d\tau}## for this radially infalling observer?
 

Similar threads

Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
  • · Replies 67 ·
3
Replies
67
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 43 ·
2
Replies
43
Views
5K