How Much Stock Should a Grocer Keep to Avoid Running Out with Less Than 1% Risk?

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SUMMARY

The discussion focuses on determining the optimal stock level for a grocer to maintain a less than 1% risk of running out of a product, assuming a Poisson distribution with an average sales rate (λ) of 4 items per week. The initial attempt to solve the problem involved calculating the probability using the formula P(X=x) = e^(-λ)λ^(x) / x!, but the participant incorrectly concluded that stocking 10 items would suffice, as P(X=10) = 0.0053. The correct approach requires calculating P(X > N) < 0.01, which translates to ensuring P(X ≤ N) > 0.99 for the stock level N.

PREREQUISITES
  • Understanding of Poisson distribution and its properties
  • Familiarity with probability calculations and factorials
  • Knowledge of basic statistical concepts such as mean and variance
  • Ability to interpret and manipulate mathematical equations
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  • Learn how to calculate cumulative probabilities for Poisson distributions
  • Explore the concept of stock management and inventory optimization
  • Study the implications of demand forecasting in retail environments
  • Investigate advanced statistical methods for risk assessment in inventory control
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Retail managers, inventory analysts, and anyone involved in supply chain management who seeks to optimize stock levels and minimize the risk of stockouts.

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Homework Statement



On the average, a grocer sells 4 of a certain article per week. How many of these should he have in stock so that the chance of his running of stock within a week will be less than 0.01? Assume Poisson distribution.



Homework Equations





The Attempt at a Solution



So I set λ = 4, plugged it into e^(-λ)λ^(x) / x! set it <0.01 and looked for an x that brought the equation to <0.01.

I was unsure how solve this for x, because of the x! in the bottom, so I just started with x = 0 and plugged and chugged till I came across x = 10, P(X=10)=0.0053 < 0.01.

However this is incorrect. Any suggestions?
 
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joemama69 said:
So I set λ = 4, plugged it into e^(-λ)λ^(x) / x!
What event does that represent the probability of in the context of this question?
Also, there is a possible ambiguity in the question. If the storekeeper stocks N items and gets requests for exactly N then technically she has 'run out', but it is not a concern to her unless there is a demand for N+1 or more.
 
Thanks for the quick reply...

From my limited knowledge of Poisson distribution, lambda represents the average rate of success, in the case of the problem at hand, an average of 4 successful sales per week.

So my thought was that given the average rate of sales = 4 per week, find the amount of stuff he should stock, 'x', so that its probability is less that 0.01.

P(X=x)<0.01 given average 4 sales per week
 
Last edited:
joemama69 said:
From my limited knowledge of Poisson distribution, lambda represents the average rate of success, in the case of the problem at hand, an average of 4 successful sales per week.
Yes, except that I would take it as the rate of opportunities to sell, i.e. requests for the item. The actual number of sales will depend on the number stocked.
So my thought was that given the average rate of sales = 4 per week, find the amount of stuff he should stock, 'x', so that its probability is less that 0.01.

P(X=x)<0.01 given average 4 sales per week
Sure, but that's the probability of exactly x requests for the item. There could be more.
 
Last edited:
joemama69 said:

Homework Statement



On the average, a grocer sells 4 of a certain article per week. How many of these should he have in stock so that the chance of his running of stock within a week will be less than 0.01? Assume Poisson distribution.



Homework Equations





The Attempt at a Solution



So I set λ = 4, plugged it into e^(-λ)λ^(x) / x! set it <0.01 and looked for an x that brought the equation to <0.01.

I was unsure how solve this for x, because of the x! in the bottom, so I just started with x = 0 and plugged and chugged till I came across x = 10, P(X=10)=0.0053 < 0.01.

However this is incorrect. Any suggestions?

If X~Po(4) is the demand and the grocer starts the week with N in stock, then he requires P(X > N) < 0.01, or P(X ≤ N) > 0.99.
 

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