How Much Stock Should a Grocer Keep to Avoid Running Out with Less Than 1% Risk?

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Homework Help Overview

The problem involves determining the appropriate stock level for a grocer to maintain, given an average weekly sale of 4 items, such that the probability of running out of stock is less than 1%. The Poisson distribution is assumed for modeling the sales.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the Poisson distribution, with some questioning the interpretation of the parameter λ and the implications of stock levels on the probability of running out. There are attempts to clarify the relationship between the average sales and the stock needed to meet demand.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and the implications of the Poisson distribution. Some guidance has been offered regarding the need to consider the probability of exceeding stock levels rather than just the probability of exact sales.

Contextual Notes

There is ambiguity regarding the definition of "running out of stock," particularly in relation to the number of items stocked versus the demand. Participants are also grappling with the mathematical complexities of the Poisson formula and its application to the problem.

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Homework Statement



On the average, a grocer sells 4 of a certain article per week. How many of these should he have in stock so that the chance of his running of stock within a week will be less than 0.01? Assume Poisson distribution.



Homework Equations





The Attempt at a Solution



So I set λ = 4, plugged it into e^(-λ)λ^(x) / x! set it <0.01 and looked for an x that brought the equation to <0.01.

I was unsure how solve this for x, because of the x! in the bottom, so I just started with x = 0 and plugged and chugged till I came across x = 10, P(X=10)=0.0053 < 0.01.

However this is incorrect. Any suggestions?
 
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joemama69 said:
So I set λ = 4, plugged it into e^(-λ)λ^(x) / x!
What event does that represent the probability of in the context of this question?
Also, there is a possible ambiguity in the question. If the storekeeper stocks N items and gets requests for exactly N then technically she has 'run out', but it is not a concern to her unless there is a demand for N+1 or more.
 
Thanks for the quick reply...

From my limited knowledge of Poisson distribution, lambda represents the average rate of success, in the case of the problem at hand, an average of 4 successful sales per week.

So my thought was that given the average rate of sales = 4 per week, find the amount of stuff he should stock, 'x', so that its probability is less that 0.01.

P(X=x)<0.01 given average 4 sales per week
 
Last edited:
joemama69 said:
From my limited knowledge of Poisson distribution, lambda represents the average rate of success, in the case of the problem at hand, an average of 4 successful sales per week.
Yes, except that I would take it as the rate of opportunities to sell, i.e. requests for the item. The actual number of sales will depend on the number stocked.
So my thought was that given the average rate of sales = 4 per week, find the amount of stuff he should stock, 'x', so that its probability is less that 0.01.

P(X=x)<0.01 given average 4 sales per week
Sure, but that's the probability of exactly x requests for the item. There could be more.
 
Last edited:
joemama69 said:

Homework Statement



On the average, a grocer sells 4 of a certain article per week. How many of these should he have in stock so that the chance of his running of stock within a week will be less than 0.01? Assume Poisson distribution.



Homework Equations





The Attempt at a Solution



So I set λ = 4, plugged it into e^(-λ)λ^(x) / x! set it <0.01 and looked for an x that brought the equation to <0.01.

I was unsure how solve this for x, because of the x! in the bottom, so I just started with x = 0 and plugged and chugged till I came across x = 10, P(X=10)=0.0053 < 0.01.

However this is incorrect. Any suggestions?

If X~Po(4) is the demand and the grocer starts the week with N in stock, then he requires P(X > N) < 0.01, or P(X ≤ N) > 0.99.
 

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