How much time does an object use to travel.

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Homework Help Overview

The discussion revolves around determining the time it takes for an object to travel 12 meters down a plane with a constant acceleration of 1 m/s² and an initial velocity of 5 m/s. The problem is situated within the context of kinematics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the rearrangement of the kinematic equation and express uncertainty about manipulating the formula to isolate time. There are mentions of using the quadratic equation and concerns about the wording of the question regarding time.

Discussion Status

The discussion is ongoing, with participants providing hints about the quadratic equation and exploring the formulation of the problem. There is acknowledgment of language barriers affecting the clarity of the question, and some participants express a need for further assistance with the fundamentals of the topic.

Contextual Notes

There are indications of potential gaps in foundational physics knowledge among participants, and the original poster expresses a need for clarification on how to set up the equation correctly.

Nerikk
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Homework Statement


How much time does the object use to travel 12m down a plane. The object has a constant acceleration of 1m/s2 and the starting velocity is 5m/s.

Homework Equations


S=V(starting velocity)*t+1/2*a*t2

The Attempt at a Solution


Here I struggle with changing the formula. I could just leave both t's on the left side and then use square root. But I have a slight feeling that this is not right.
 
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I could just leave both t's on the left side and then use square root. But I have a slight feeling that this is not right.
Very close - for that to work, the LHS needs to be a complete square.

Hint: quadratic equation

Aside:
I'm intrigued by the wording. Is time the sort of thing that gets used up by objects ... you know, like a car uses petrol?
Probably the question wants to know how much time is taken or occupied by an activity.
 
Yea, it's quite hard to word yourself correctly in another language. Especially in math. But I will check out quadratic equation! Thank you!
 
Oh it was a translation?! Well done - I couldn't tell. I wondered if maybe you just had a new-age physics teacher ;)
Since English is a second language ... I'll say a bit more.
The equation you are trying to solve can be put in form: ##At^2+Bt+C=0## - do so: A, B, and C, may be made of several variables.
You should recognize that as the equation for the roots of a parabola... you should know an equation to solve that. $$t\in \frac{-B\pm\sqrt{B^2-4AC}}{2A}$$
 
I think I need some more help on that one. First of all how do I achieve 0 on the right side of the equation. Second how do I determine the variables?

And thank you for all your help! It seems like I lack some fundamentals in physics, heh...
 

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