How Much Voltage and Current Do I Need for 8 LEDs in Series and Parallel?

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SUMMARY

To power 8 LEDs in series, a total of 24V and 30mA is required from the power supply, resulting in 720 milliwatts of power consumption. In a parallel configuration, the voltage remains at 3V, but the total current increases to 240mA, with each LED still drawing 30mA. It is advisable to use a resistor in series to stabilize the current, as LED performance is sensitive to voltage and temperature variations. A 12V DC supply can be utilized effectively by configuring the LEDs in series with appropriate resistors to maintain current control.

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ChrisToffer
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If i have a LED which drops 3V, and 30mA through each LED and i need 8 LED in series.. does it mean that i need a total of 24V and 30mA from power supply or less?
And if i use the same circuit in parallel, does it mean i will use 3V but much more current like 0.24A?? or least current?
 
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For your series circuit, I believe you would need at least 24 volts at 30 ma.

That's 720 mwatts from your source.

For parallel, 3 volts will work with 240 ma coming from source, yet each branch will get it's 30ma.

That's also 720 mwatts from your source.
 
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ChrisToffer said:
If i have a LED which drops 3V, and 30mA through each LED and i need 8 LED in series.. does it mean that i need a total of 24V and 30mA from power supply or less?
Why less? You'll need 24V and 30mA. It is safer to use a voltage a bit above 24V together with a suitable resistor in series.

And if i use the same circuit in parallel, does it mean i will use 3V but much more current like 0.24A?? or least current?
8*30mA of course. The same advice: use a resistor in series.
 
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LED current is highly sensitive to applied voltage and temperature.
Each parallel path will require a resistor to stabilise the current in that path.

Consider a 12.00 volt DC supply for 8 LEDs.
4 LEDs in series would give no control of current at varying temperatures.

3 LEDs and a 100 ohm resistor in each series chain would stabilise the current at 30 mA. One of the three chains will need an extra 100 ohm resistor or a hidden LED to make 8 visible LEDs total.

2 LEDs with 200 ohms in series will be less efficient than 3 LEDs with 100 ohms.
 
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Most likely this can only be answered by an "old timer". I am making measurements on an uA709 op amp (metal can). I would like to calculate the frequency rolloff curves (I can measure them). I assume the compensation is via the miller effect. To do the calculations I would need to know the gain of the transistors and the effective resistance seen at the compensation terminals, not including the values I put there. Anyone know those values?

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