The work required to accelerate a mass of 60,000 kg from 2 m/s to 60 m/s is calculated using the kinetic energy formula, specifically ΔKE = 0.5 * m * (v₂² - v₁²). The correct approach involves determining the change in kinetic energy, which results in a positive value when calculated as A_res = (60,000 kg / 2) * (60² - 2²). The initial miscalculation arose from using the wrong formula, leading to an incorrect negative result.
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The change in kinetic energy is positive: \Delta KE = \Delta (mv^2/2) = .5m(v_2^2-v_1^2)Ockonal said:Homework Statement
What work needs to be done to change body speed with mass 6×10⁴ kg from 2 m/s to 60 m/s?Homework Equations
A = mgh
A = FS
A = mv²/2The Attempt at a Solution
A₁ = mV₁² / 2
A₂ = mV₂² / 2
A_res = A₂ - A₁;
A_res = m/2 × (V₁² - V₂²)
A_res = 3×10⁴ × (4 - 3600)
The result is negative and too big. Is that right?