How powerful should the magnet be to repel against gravity?

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SUMMARY

The discussion centers on calculating the necessary magnetic force to counteract gravitational force for a magnet. The gravitational force is determined using Newton's law, specifically the formula F = Gm1m2/r², where m1 is the mass of the Earth and m2 is the mass of the magnet. To achieve upward repulsion, the magnetic force must exceed this gravitational force, which can be expressed as F = m2g, where g is the gravitational constant at the Earth's surface. Participants emphasize the need for the magnetic force to be greater than the calculated gravitational force to achieve the desired effect.

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  • Understanding of Newton's law of universal gravitation
  • Familiarity with magnetic force calculations
  • Knowledge of gravitational constant (g)
  • Basic physics concepts related to force and motion
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Physics students, engineers, and hobbyists interested in magnetism and gravitational forces will benefit from this discussion.

spidey
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i have two magnets and i want to repel one magnet against gravitational force upwards..so how powerful the magnet should be?i can calculate the gravitational force using Newton's law f=gm1m2/r2 where m1 is mass of Earth and m2 is mass of one magnet...so the magnetic force should be greater than this force ...help me...
 
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You require the force on the magnet to be equal to the force of gravity, as you said.

F = I \Delta l B sin \theta = \frac{Gm_{1}m_{2}}{r^{2}}
 
spidey said:
i have two magnets and i want to repel one magnet against gravitational force upwards..so how powerful the magnet should be?i can calculate the gravitational force using Newton's law f=gm1m2/r2 where m1 is mass of Earth and m2 is mass of one magnet...so the magnetic force should be greater than this force ...help me...

Hi spidey! :smile:

Technically, it's Gm1m2/r2,

but we can write Gm1/r2 = g, the usual gravitational constant at the Earth's surface,

so f = Gm1m2/r2 = m2g. :smile:
 

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