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How short a distance to come to a stop without sliding?

  1. Nov 5, 2008 #1
    A railroad car has crates in it with a coefficient of .5 w/ the car's floor. The train is moving at 22m/s, how short a distance can it be stopped w/o letting the crates slide?


    Fnet = 0 because you don't want sliding.
    a = coefficient of static friction x gravity



    When I solved for a, I got 4.9m/s2. I know if I multiply this by the mass of the crates, it should be equal to the static friction force.

    I think I have to take the derivative of the velocity to get acceleration, and the antiderivative of velocity to get distance, but how do I do this with no other variables?
     
  2. jcsd
  3. Nov 5, 2008 #2
    I've not checked the working for the earlier part of the question.

    Draw sketches of the train at the start and the end of the problem, write on all the values you know, and see what equations you might be able to use. (Think kinematics.)
     
  4. Nov 5, 2008 #3

    Redbelly98

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    You have the initial velocity and the acceleration. You can find distance traveled from that information.
     
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