How should I show that solutions can be expressed as a Fourier series?

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SUMMARY

The discussion focuses on expressing solutions of the differential equation ## \ddot{x}+x=0 ## as a Fourier series. The general solution is identified as ## x(t)=A\sin\omega t+B\cos\omega t ##, with the specific case of ## \omega=1 ## leading to the simplified form ## x(t)=A\sin\omega t ##. The user seeks guidance on how to demonstrate that solutions with angular frequency ## \omega ## can be represented as a Fourier series, specifically by substituting the series form into the differential equation to analyze the coefficients.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear equations.
  • Familiarity with Fourier series and their representation of periodic functions.
  • Knowledge of angular frequency and its role in oscillatory systems.
  • Ability to manipulate and substitute mathematical expressions in equations.
NEXT STEPS
  • Study the derivation of Fourier series for periodic functions.
  • Learn how to apply the method of substitution in differential equations.
  • Explore the properties of sine and cosine functions in relation to angular frequency.
  • Investigate the convergence criteria for Fourier series expansions.
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with oscillatory systems and Fourier analysis. This discussion is particularly beneficial for those looking to deepen their understanding of differential equations and their applications in expressing solutions as Fourier series.

Math100
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Homework Statement
Consider the equation ## \ddot{x}+x+\epsilon(\alpha x^2\operatorname{sgn}(x)+\beta x^3)=0, 0<\epsilon<<1, \alpha>0, \beta>0 ##, where ## \alpha ## and ## \beta ## are constants, and the signum function, ## \operatorname{sgn}(x) ##, is defined by ## \operatorname{sgn}(x)=1 ## for ## x>0 ##, ## \operatorname{sgn}(x)=0 ## for ## x=0 ## and ## \operatorname{sgn}(x)=-1 ## for ## x<0 ##. With initial condition ## x(0)=0 ##, show that solutions with angular frequency ## \omega ## can be expressed as a Fourier series of the form ## x(t)=\sum_{k=1}^{\infty}B_{2k-1}\sin((2k-1)\omega t)=B_{1}\sin\omega t+B_{3}\sin 3\omega t+\cdots ##.
Relevant Equations
None.
Proof:

Let ## \epsilon=0 ##.
Then the unperturbed equation is ## \ddot{x}+x=0 ## and the general solution is
## x(t)=A\sin\omega t+B\cos\omega t ## where ## \omega=1 ## is the angular frequency
with the constants ## A ## and ## B ##.
With the initial condition ## x(0)=0 ##, we have that ## B=0 ##.
This gives ## x(t)=A\sin\omega t ## where ## A ## is a constant.
Note that the function of ## x(t)=A\sin\omega t ## is periodic and odd.

From the work/proof shown above, how should I show that solutions with angular frequency ## \omega ##
can be expressed as a Fourier series of the given form on the problem? What needs to be done?
 
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Math100 said:
From the work/proof shown above, how should I show that solutions with angular frequency ## \omega ##
can be expressed as a Fourier series of the given form on the problem? What needs to be done?
Can you show the work you've done on this problem so far?
 
renormalize said:
Can you show the work you've done on this problem so far?
That's all the work I have so far.
 
Math100 said:
That's all the work I have so far.
OK, can you substitute the form ##x(t)=\sum_{k=1}^{\infty}B_{2k-1}\sin((2k-1)\omega t)=B_{1}\sin\omega t+B_{3}\sin 3\omega t+\cdots## into the differential equation to see what you can learn about ##\omega## and the coefficients ##B_{2k-1}##?
 

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