How Small Must a Bone Be to Detect a 5% Change in X-ray Imaging Intensity?

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Homework Help Overview

The problem involves determining the smallest diameter of a bone that can be detected in an X-ray image, given a specific change in intensity and the absorption length of bone. The context is related to imaging techniques and the physics of X-ray absorption.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the setup of the exponential equation related to intensity changes and absorption length. There are attempts to clarify the dimensions of the variables involved and the definitions of terms like absorption length and absorption coefficient.

Discussion Status

Participants are actively engaging with the problem, questioning the setup and definitions used. Some guidance has been offered regarding the interpretation of absorption length, but there is no explicit consensus on the correct approach or solution yet.

Contextual Notes

There is confusion regarding the terminology used, specifically the distinction between absorption length and absorption coefficient. Additionally, the absence of explanations for the practice problems is noted as a constraint affecting understanding.

jdemps
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Homework Statement



Imagine a 10 cm thick slab of flesh. If your x-ray imager can reliably identify a 5% change in intensity from one location to another in an image, what is the smallest diameter bone you are going to be able to make detect in your x-ray image?

Absorption length of bone: 0.017 m

Homework Equations



I=I0e-μx

The Attempt at a Solution



I tried letting 0.05=e-μx letting 0.017m be μ. The correct answer is supposed to be 1.3 mm but I can't seem to get that.
 
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1. going from 1 to 0.05 is a change of 0.95. Consider going from I = 1 to I = 0.95.
2. μx must have no dimension, otherwise you can't exponentiate it. your exponent has the wrong dimension...
3. What is the definition of absorption length in your context ? I = I0 / e or I = I0 / 2 ?
 
I set it up so that 0.95=e-μx trying to let μ=1/0.017 so that x could be in meters without having units in the exponent. That did not work either when trying to solve for x. There are no explanations for these practice problems and I have only ever heard the term "absorption coefficient" not absorption length, which is why I'm confused.
 
"Did not work either" means you found 0.017 m * ln(0.95) = 0.00087 m ?

I agree the most common maeening for absorption length is length over which I = I0 / e.

It's just because your 'right' answer corresponds to 0.017 m * 2log(0.95) that I asked for this context.

I can't think of anything else to help you with at this moment (bedtime+3h)...:frown:
 

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