How the charge imbalance in a plasma changes with time

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SUMMARY

The discussion focuses on the dynamics of charge imbalance in plasma, specifically how the net charge density, represented as ##\rho_q = e\delta##, influences the electric field ##\mathbf{E}## over time. The user attempts to apply Maxwell's equations, particularly the fourth equation, leading to the continuity equation ##e\dot{\delta} + \nabla \cdot \mathbf{J} = 0##. The conversation emphasizes the relationship between charge deviation and the resultant electric field, highlighting the feedback loop between charge distribution and electric field generation.

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  • Understanding of Maxwell's equations, particularly the fourth equation.
  • Familiarity with plasma physics concepts, including charge density and electric fields.
  • Knowledge of continuity equations in electromagnetic theory.
  • Basic grasp of vector calculus as it applies to electromagnetic fields.
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  • Study the derivation of the continuity equation in plasma physics.
  • Explore the implications of charge density variations on electric field dynamics.
  • Investigate the role of electric fields in plasma stability and behavior.
  • Learn about numerical methods for simulating plasma dynamics and charge distributions.
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Researchers in plasma physics, electrical engineers, and students studying electromagnetic theory who are interested in understanding the behavior of charge imbalances in plasma systems.

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Homework Statement
There's a neutral plasma of protons and electrons of density ##\rho##. If the number of electrons per unit volume fluctuates around its mean value by a small amount ##\delta(\mathbf{x}, t)##, show that ##\ddot{\delta} + (\rho e^2/\epsilon_0 m_e m_p) \delta = 0##.
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I put the net charge density ##\rho_q = e\delta## so that ##\nabla \cdot \mathbf{E} = e\delta / \epsilon_0##, then I tried Maxwell IV:\begin{align*}
\dot{\mathbf{E}} + c^2 \mu_0 \mathbf{J} &= 0 \overset{\mathrm{div}}{\implies} e\dot{\delta} + \nabla \cdot \mathbf{J} = 0
\end{align*}but this just gives you back the continuity eq. How to start?
 
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This is often derived with the following logic: the charge deviation causes an electric field to be produced, and then the charges respond to that electric field.
 
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