chhitiz
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if there is a hollow cylinderical hole with maximum internal pressure P in a hollow casing which is likw a cylindrical shell, how do we get how thick the walls will be?
How thick should the walls be?
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if there is a hollow cylinderical hole with maximum internal pressure P in a hollow casing which is likw a cylindrical shell, how do we get how thick the walls will be?
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cstoos
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P=[tex]\frac{2tSE}{D-2tY}[/tex]
Where:
t = wall thickness
S = Maximum allowable stress
E = Material Quality Factor
Y = Wall thickness coefficient
D = Outer diameter
At least, that is according to http://www.pumpfundamentals.com/applets.htm#problems_viewing
That is according to ASME B31.3
Where:
t = wall thickness
S = Maximum allowable stress
E = Material Quality Factor
Y = Wall thickness coefficient
D = Outer diameter
At least, that is according to http://www.pumpfundamentals.com/applets.htm#problems_viewing
That is according to ASME B31.3
chhitiz
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i think you misunderstand. it is not a pipe. the casing is solid metal and the only part that is hollow is the cylindrical hole, perpendicular to the plane of the shell. now, what is the minimum thickness required for the casing to withstand a given pressure, when we know the inner radius of solid shell, and radius of hollow cylidrical hole.