How Thick Should the Stainless Steel Plate Be in a Burst Test Chamber?

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SUMMARY

The discussion focuses on determining the required thickness of a stainless steel plate for a burst test chamber designed to withstand the pressure exerted by a brass fitting weighing 202 grams at 150 bar (15,000 kPa). The calculation involves using the formula P=F/A, where the force (F) is derived from the weight of the fitting multiplied by the acceleration due to gravity (9.8 m/s²). The necessary thickness of the stainless steel plate can be calculated based on the pressure and the area of contact to ensure no dents occur during the test.

PREREQUISITES
  • Understanding of pressure calculations in physics
  • Familiarity with the properties of stainless steel
  • Knowledge of basic mechanics and material strength
  • Ability to perform calculations involving force and area
NEXT STEPS
  • Calculate the force exerted by the brass fitting using F=mg
  • Research material strength properties of stainless steel
  • Learn about safety factors in pressure vessel design
  • Explore engineering standards for burst test chamber construction
USEFUL FOR

Mechanical engineers, materials scientists, and anyone involved in designing pressure vessels or conducting burst tests will benefit from this discussion.

HaaJeHaa
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Not really a homework question, but it could be. Working on making a burst test chamber and need some calculations that says it is safe enough. Sorry for my poor english, it's not my first language.

Homework Statement



The setup: First a brass fitting would be fitted inside a chamber, and then pressurize until burst. I would like to know how much stress the bursting object gives to the surface of the chamber.

My current numbers:
Fitting weight: 202grams.
Pressure: 150bar (=15000kPa)
Diameter inside the pressurehose: 15.23mm
Length to nearest surface: 5cm
Length to bottom of chamber: 15cm

Do I/you need more numbers?

How thick stainless steel plate will I need so the 202gram object pressurized at 150bar won't give dents?

Thank you!

Homework Equations



P=F/A

The Attempt at a Solution



Not sure...
 
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you could calculate the force of the object, which is equal to the weight (202g) times the acceleration due to gravity (9.8 m/s^2). This will give you the force, which you can then use in the equation P=F/A to calculate the required area for the pressure. You can then calculate the necessary thickness of the plate using the area.
 

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