How to Calculate Absolute Gamma Probability from Relative Intensities?

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Discussion Overview

The discussion revolves around calculating absolute gamma probabilities from relative intensities listed in tables of nuclides following alpha or beta decay. Participants explore the implications of these probabilities and their relationship to decay processes.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant seeks to understand how to convert relative intensities of gamma emissions into absolute probabilities that sum to one.
  • Another participant questions the meaning of "absolute gamma probability" and discusses the nature of decay processes, noting that a nucleus can be left in an excited state after decay.
  • A participant explains that the total of relative probabilities can exceed one due to the possibility of multiple gamma emissions occurring from a single decay event.
  • One participant expresses concern that for calculations related to activity and mass, the total probability must be less than one, suggesting that errors in summing probabilities may lead to impractical results.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to calculate absolute gamma probabilities, and multiple competing views regarding the interpretation of relative intensities and their implications remain present.

Contextual Notes

There are unresolved assumptions regarding the definitions of probabilities and the nature of gamma emissions, as well as potential errors in the summation of probabilities that may not have been observed.

HaniNaber
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Hi All,

I want to ask how to calculate the absolute gamma probability from relative intensities ( found on the tables of nucliedes) following alpha or beta decay.

I mean the probabilities that all add to 1.

Many thanks.
 
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HaniNaber said:
the absolute gamma probability from relative intensities
I'm not sure what one means by "the absolute gamma probability". To what 'probability' is one referring. After alpha or beta decay, a nucleus of a radionuclide can be left in an excited state, and the only way to become more stable is to emit a gamma ray. A given gamma energy has a probability of occurring when compared to all the other possible decays, and some of more likely to happen, or more probable, depending on precursor decay.

To what 'chart of the nuclides' is one referring?
 
I mean in the table of nuclides for example the IAEA table , they would list the relative intensities of all the gammas from one isotope for example one gamma from the 4th energy level to the 2nd and one from the 2nd to ground state, after adding all the relative probabilities of all the possible gammas listed they don't add to one (after adding all of them the total is 1.4 for Ac228), I'm looking to convert these relative intensities to probabilities that add to 1.

Thank You.
 
HaniNaber said:
I mean in the table of nuclides for example the IAEA table , they would list the relative intensities of all the gammas from one isotope for example one gamma from the 4th energy level to the 2nd and one from the 2nd to ground state, after adding all the relative probabilities of all the possible gammas listed they don't add to one (after adding all of them the total is 1.4 for Ac228), I'm looking to convert these relative intensities to probabilities that add to 1.

Thank You.
Well, the reason that probabilities for all gamma ray energies can add up to >1 is that in some decays two gamma rays are produced successively, i.e., they both happen successively from the same decay. One sees this in radiative capture of neutrons as well, where the excited nucleus emits 1 or 2 gammas in response to absorption of a neutron. The energy of the two gammas is often nearly equal to the single gamma energy.

https://www.nndc.bnl.gov/nudat2/getdecayscheme.jsp?nucleus=228TH&dsid=228ac bM decay&unc=nds
 
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Thank you, it makes sense.

I am trying to do some calculations related to activity and mass based of the total probability of all the gammas, and for this calculation to be done, the total probability should be less than 1, otherwise I would get negative masses.

I think that accumulation of error in adding all the possible probabilities ( some might have never been observed) is the reason for greater than 1 total probability. It might just be impractical to do so.

Thanks again for your help.
 

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