How to calculate Battery run-time?

Click For Summary
To calculate battery run-time for a UPS supplying a PC, it's essential to consider both the amp-hours and the voltage of the battery. For a 24V, 1500Ah UPS, the raw capacity is 36kWh, allowing for approximately 240 hours of theoretical run-time at 150W consumption, though practical usage should account for at least a 10% efficiency loss. It's crucial to differentiate between watts and volt-amperes, as consumer battery backups are typically rated in VA, not watts, affecting the actual run-time. For example, a 1500VA UPS may only support 900W to 600W due to varying power factors, which can significantly reduce expected run-time. Therefore, accurate calculations must include these factors to avoid overestimating performance.
Artahir
Messages
2
Reaction score
0
I can't get my head around question about energy consumption, energy supply and run-time. I think I forgot (Im sure I forgot) something in my equation. I am trying to find a way to calculate for how long could UPS supply my PC I don't know why I can't find Amp-hours of UPC on it but let's assume it's 1500Ah and my PC consumption is 150W. I tried to do some digging first I found some explanations but none of them made sense to me I feel like it can't be so complicated. Or when I found easier equations it didn't make sense (the result). could anyone give me answer?
 
Engineering news on Phys.org
What voltage is the battery in the UPS? If it is 24V, 1500Ah you have a raw capacity of 24⋅1500Wh=36kWh. Divide by 150W and you get 240h.

This is just a coarse calculation, assume at least 10% less going from theory to practice.
 
Svein said:
What voltage is the battery in the UPS? If it is 24V, 1500Ah you have a raw capacity of 24⋅1500Wh=36kWh. Divide by 150W and you get 240h.

This is just a coarse calculation, assume at least 10% less going from theory to practice.
Exactly this is my calculation which I tried based on my logical assumption. but I used Voltage 230 AC for my desk PC and it doesn't make sense because if you add Voltage it means more hours and with 230 Iam around 2k hours which is stupid right?
 
You need volt-amp-hours, not amp-hours. An APC 1500 (retail $400, so you know where that fits in their product line) stores 220 V-A-hours. (792 kJ in SI) That has the energy needed to run a 150 W device for 88 minutes: 720,000 kJ / 150 W = 5280s = 88 minutes. This is an absolute upper limit: you don't have perfect efficiency, and you can't get the last bit of charge out of the battery. APC claims 50 minutes for that load.
 
  • Like
Likes davenn
Watch out for Watts versus Volt-Amps. Consumer Battery Backup devices are advertised in VAs not Watts. Usually the Power Factor is 0.6 but some of the off-brand ones use a Power factor as low as 0.4. So a 1500VA rating could be anywhere between 900W and 600W; that is the level that the overload shutdown is set for. Also, many modern computer power supplies have Power Factor Correction built-in to keep their power factor high, 0.8 to 0.95. That being the case, the actual runtime could be only 1/2 of the 'computed' runtime. And no-load losses of Battery Backup also seem to be significant but I haven't measured them.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
7
Views
3K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
27
Views
4K