- #1

Johnk690

- 3

- 0

(Ignor this unless you think iv made a mathematical mistake)

(1400N*.175m), which provides a torque on the drive cog, (245Nm/0.085m)= 2882N which is the tension in the chain, multiplied by the raduis of the back cog 0.035= 100Nm of torque at the back cog, dividing this by the radius of my back wheel i get 305N

Is this 305 N my linear force forward? and divided by the total mass 120kg my acceleration 2.54 m/s^2

I know I have no friction forces ie rolling resistance or air resistance friction at bearing etc.

I thought I understood moments of inertia but i didnt know how to include the mass of the person plus bicycle in them, any help would be much appreciated