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Relevant Equations:

F=ma

W = Fcosθ(d)

Ek = 1/2mv^2

Eg = mgh

Fx = kx

Ee = 1/2kx^2

d = v1t + 1/2at^2

v2^2 = v1^2 +2ad

Attempting the Calculations:

mass of beanbag = 0.048kg

distance needed to travel = lets say 10m

Fx = 10N (using a spring force gauge)

x = 0.25m

launch angle = 50 degrees

Fx = kx

10 = k(0.25)

k = 40N/m

Ee = 1/2kx^2

= 1/2(40)(.25)^2

= 1.25

In the beginning it has elastic and gravitational potential energy so

Ee = Eg

1.25 = 0.048(9.8)h

h = 2.657m is this the max. height of the bean bag?

I'm thinking I need to solve for acceleration and velocity so that I can use

v2^2 = v1^2 = 2ad and that would be my distance, then I can work backwards using different distances and solve for Fx and x, but then I think I also need to use the launch angle in the calculations, and I don't know where to do that.

Thanks for looking at my post.