How to Calculate Center of Pressure (hf) for a Tank?

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The center of pressure (hf) is defined as the point where a single supporting force would balance the total fluid force acting on one side of a lamina. This concept ensures that the net torque from the fluid about the center of pressure is zero. The calculation involves integrating the product of the fluid force and the distance from the center of pressure, represented by the equation ##\int F(y).(y-c).dy=0##. Understanding this relationship is crucial for accurately determining the center of pressure in fluid mechanics. Proper calculation of hf is essential for applications involving tanks and fluid dynamics.
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Homework Statement
I'm trying to fully understand the calculation of, the center of pressure (hf), for a vertical tank wall with a fluid of uniform density. The pressure distribution is linear, starting from zero at the surface and increasing to ρgh at the bottom.

Specifically, I would like to understand:
-The general derivation of the center of pressure hf
Relevant Equations
I’m aware of the formula hf=(∫h⋅dF)/F Where F is the resultant force on the wall of the tank.
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The idea of the centre of pressure is that it is the point where a single supporting force on one side of a lamina would balance the total force from the fluid on the other side.
So the net torque from the fluid about that point is zero.
If its height is c then ##\int F(y).(y-c).dy=0##.
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

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