How to calculate current of a resistor inside of another parallel resistor?

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The discussion focuses on calculating the current through a resistor within a complex parallel resistor network. The equivalent resistances of various resistor combinations were calculated, leading to a total resistance of 8 ohms and a total current of 3A. The voltage drop across certain resistors was determined to be 15V, which helped in finding the current through R2 as 1.5A. The user expressed confusion about calculating the current in R5 but concluded that the current through R5 should match the current through the parallel resistors. Overall, the calculations confirmed the user's understanding of the circuit's behavior.
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How to calculate current of a resistor "inside" of another parallel resistor?

The 1st image is how he drew it for us, no text.. I guess because it's quite complicated.
He asks a bunch of questions, I've answered..
1. Equivalent resistance of R3 and R4=5 ohms
2. combined resistance of R6 and R7=9 ohms
3. combined resistance of R9 and R10? =9 ohms
4. equivalent resistance from D to E? 3 ohms
5. Equivalent resistance from B to E?
---
this one was kind of tricky.. but I think I got it right.. 5 ohms? I calculated the equivalent resistances of R(3,4) and R(6,7,8,9,10), added it to R5.. Now, R(3-10) acts parallel to R2... blah blah, 5 ohms for R(2-10).
6. total resistance? 5 ohms of the parallels and 2 and 1 makes 8.
7. total current? 3A
8. Potential drop occurs across R1? 6V
9. Drop in potential from B to E? 15V
10. Current in R2? 1.5A
:confused: 11
Current in R5? How come I got R2 but not R5?
"9. Drop in potential from B to E? 15V"
Vt in parallel is equal to "everything", by everything, meaning "one and one".. or something.. So yeah, I'm positive that V2 is 15V.. and V(3-10) is 15V.. But how do I find the V5 to find out the I5.. Thanks..
--
Also just figured that I(3-10)=1.5A..
"$ 1 5.0E-6 10.391409633455755 50 5.0 43
w 64 368 64 208 0
v 64 208 64 176 0 0 40.0 24.0 0.0
w 64 176 64 96 0
w 64 96 144 96 0
r 144 96 176 96 0 2.0
w 176 96 272 96 0
w 272 96 272 192 0
r 272 192 272 240 0 10.0
w 272 240 272 368 0
w 272 368 208 368 0
r 208 368 176 368 0 1.0
w 176 368 64 368 0
w 272 96 480 96 0
w 480 96 480 112 0
w 480 112 416 112 0
w 480 112 544 112 0
r 544 112 544 144 0 10.0
r 416 112 416 144 0 10.0
w 416 144 480 144 0
r 480 144 480 176 0 2.0
w 544 144 480 144 0
w 480 176 544 176 0
w 480 176 416 176 0
r 416 176 416 192 0 7.0
r 544 176 544 192 0 6.0
w 416 192 416 208 0
w 544 192 544 208 0
r 416 208 416 224 0 2.0
r 544 208 544 224 0 3.0
w 416 224 480 224 0
w 480 224 480 208 0
r 480 208 480 192 0 9.0
w 480 176 480 192 0
w 544 224 480 224 0
w 480 224 480 368 0
w 480 368 272 368 0"
http://www.falstad.com/circuit/
This has confirmed my other answers.. still want to know number 11 and past, how to do them.
 

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Meh.. anyhow, I came upon kind of a breakthrough..
I got 15V for the voltage of the non serialized resistors.. An in a parallel, all "total" resistors have equal voltage.. So V2 equals V(3-10[sans 2])
15V=V2=V(3-10[sans2)..
With V2, and te given R2, I got I2 of 1.5A.. and in a circuit, total current is equal to current of the series, or the sum of the parallel's.. So if It=3A..and I2=1.5A.. V(3-10[sans2])=1.5A.. and since R5 is in a series with R(3-4), R(6-10), it's current is equivalent to the other's.. So V5=1.5A?? And yeah..couple hours til I get to his class anyhow..
 
Case closed..and the rest of the answers that I came up with match the falstad.com data thing;;:)
 
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