Problem solving for current in parallel resistors

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SUMMARY

The discussion centers on solving current flow through individual resistors in a parallel circuit, specifically referencing a problem where the total current is 1.2 A with a voltage of 15 V. Participants clarify that the voltage across parallel resistors is not uniformly 15 V due to potential drops across other resistors in the circuit. To accurately determine the current through each resistor, it is essential to calculate the equivalent resistance of the parallel configuration and apply the current divider rule or find the total current first.

PREREQUISITES
  • Understanding of Ohm's Law (I = V/R)
  • Knowledge of parallel resistor configurations
  • Familiarity with the current divider rule
  • Ability to calculate equivalent resistance in parallel circuits
NEXT STEPS
  • Study the concept of equivalent resistance in parallel circuits
  • Learn how to apply the current divider rule in practical problems
  • Practice solving DC circuit problems involving multiple resistors
  • Review potential drop calculations across resistors in series and parallel
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone looking to deepen their understanding of circuit analysis, particularly in parallel resistor configurations.

Kavorka
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Homework Statement



I am able to solve most of the DC circuit problems we're given, but I seem to be missing something conceptually when it comes to finding current that passes through individual resistors when they are in parallel. An example problem would be #10 at this link:

http://www.ahsd.org/science/stroyan/APPhysics/ch17/apc1718wq/APC17WQ4.HTM

Where the correct answer is 1.2 A.

2. Homework Equations


I know that I = V/R, and that in parallel resistors the voltage is divided equally between branches and the voltage in each branch is equal to the original, which is 15 V in this case.

The Attempt at a Solution


What I'm not sure is what resistance to plug in. According to the problem the resistance to use would be 12.5 ohms (R = V/I = 15 V / 1.2 A). I have no idea where this equivalent resistance came from and why it's used for the 2.7 ohm resistor. Any pointers would be appreciated!
 
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Kavorka said:
I know that I = V/R, and that in parallel resistors the voltage is divided equally between branches and the voltage in each branch is equal to the original, which is 15 V in this case.
Ah. Well the problem is that is not true (the 15 V statement). Current passing from A to B passes through the 3.2 and 3.6 Ohm resistors, too, and they will both cause a potential drop. So your parallel paths will not have a 15 V potential across them but something less depending upon the drops on those resistors.

One way to proceed would be to (temporarily) combine the parallel resistances into a single resistance and determine the current in the circuit. Then you can either use that current to find the potential drop across this new resistor, hence the potential difference for the original parallel connection, or you can use the current divider rule.
 

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