How to calculate differential work done by a force in circular motion?

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SUMMARY

The discussion focuses on calculating the differential work done by a force in circular motion. The correct expression for the differential displacement is identified as d\boldsymbol{r} = d\boldsymbol{\theta} \times \boldsymbol{r}. The vector d\boldsymbol{\theta} = \hat{\boldsymbol{n}}d\theta indicates the direction of rotation, adhering to the right-hand rule. The mention of the minus sign relates to the orientation of the vectors involved in the calculation.

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zenterix
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Homework Statement
When dealing with differential vectors, I still struggle sometimes.

I'd like to calculate the differential of work done by a force acting on a particle mass undergoing circular motion
Relevant Equations
Let ##\vec{r}## be the vector from the center of the circular motion to the particle.

I believe I can write the equation below, but I am not sure if it is an equality or an approximation.

$$d\vec{r}=\vec{r} \times d\vec{\theta}$$

$$dW=\vec{F} \cdot d\vec{r}$$
$$=\vec{F} \cdot (\vec{r} \times d\vec{\theta})$$

$$=(\vec{F} \times \vec{r})\cdot d\vec{\theta}$$

$$=-(\vec{r} \times \vec{F})\cdot d\vec{\theta}$$

$$\implies dW=-\vec{\tau} \cdot d\vec{\theta}$$
My question is, is this correct, and if so, why the minus sign?
 
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The only mistake is in the first line, which should be ##d\boldsymbol{r} = d\boldsymbol{\theta} \times \boldsymbol{r}##. The vector ##d\boldsymbol{\theta} = \hat{\boldsymbol{n}}d\theta## points along the rotation axis, and ##\theta## increases in the direction given by the right hand rule.
 
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