How to Calculate Electric Field of Half Spherical Shell with Gauss Law?

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Homework Help Overview

The discussion revolves around calculating the electric field of a half spherical shell with a uniform surface charge density along its axis of symmetry. The original poster considers using Gauss's law but expresses uncertainty about the appropriateness of their approach due to the open nature of the Gauss surface above the shell.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster suggests calculating the electric field for a full spherical shell and then dividing by two. Some participants question this approach, considering the geometry of the charge distribution and the implications of using a closed surface for Gauss's law.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the assumptions made regarding the symmetry and charge distribution. Some guidance has been offered, but no consensus has been reached on the best approach.

Contextual Notes

Participants are grappling with the challenge of finding a suitable closed Gauss surface for the half spherical shell and the implications of the geometry on the electric field calculation.

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Homework Statement



Hey guys.
I got this question:
"Calculate the electric field of half a spherical shell with radius R and uniform surface charge density [tex]\sigma[/tex] along its axis of symmetry above the shell."
I guess I shell use Gauss law, the thing is that the Gauss surface will not be closed above the half spherical shell so I though about calculating the electric field for a full spherical shell and then divide it by 2 to get the electric field above the upper half spherical shell.
What do you say? is that the way to go?

Thanks in advance.

Homework Equations





The Attempt at a Solution


 
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If you're talking about losing the half away from the side that is charged, I'd think not.

From the statement I take it that the points along the axis make the charges look like concentric rings spaced at a distance according to their spherical geometry away from whatever point you are at. Like looking down at a salad bowl turned face down?
 
LowlyPion said:
If you're talking about losing the half away from the side that is charged, I'd think not.

From the statement I take it that the points along the axis make the charges look like concentric rings spaced at a distance according to their spherical geometry away from whatever point you are at. Like looking down at a salad bowl turned face down?

Yeah, it's like a salad bowl turned face down :smile:
I need to find a closed Gauss surface that will contain this "bowl" and I can't think of one.

I'm sorry, I didn't understand what you mean by "If you're talking about losing the half away from the side that is charged, I'd think not.".

Thanks a lot.
 
I didn't understand what you mean by ...
I was simply referring to your notion that you would take the integral of a whole sphere and then take away the mirror of the salad bowl.
 

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