How to Calculate Electric Potential Energy in an Infinite Grid of Charges?

Click For Summary
SUMMARY

The discussion focuses on calculating the electric potential energy of a single cation in an infinite one-dimensional grid of alternating anions and cations, each with a charge of ±1e. The participants reference the formula for potential energy between two charges, W = 1/(4πε₀) * (q₁ * q₂)/r, and explore the implications of summing contributions from an infinite number of charges. A participant arrives at the equation φ = k * ∑(n=1 to ∞) (1/n * (-1)^(n+1) * q/r), but questions its convergence, ultimately resolving their confusion independently.

PREREQUISITES
  • Understanding of electric potential energy and Coulomb's law
  • Familiarity with infinite series and convergence concepts
  • Basic knowledge of electrostatics and charge interactions
  • Proficiency in mathematical summation techniques
NEXT STEPS
  • Study the concept of electric potential energy in electrostatics
  • Learn about convergence of infinite series in mathematics
  • Explore the implications of alternating series in physics
  • Investigate the behavior of electric fields in infinite charge distributions
USEFUL FOR

Physics students, electrical engineers, and researchers in electrostatics seeking to deepen their understanding of potential energy in complex charge configurations.

Icheb
Messages
42
Reaction score
0
Following exercise:
There is a one dimensional grid of infinite size and it consists of anions and cations (each with a charge of 1e / -1e) like this:

acacacac

The distance between the anions and cations is 5*10^-10m.
Now I am supposed to calculate the electrial potential energy of one cation alone. I know that, if I only have two charges, the energy would come from

W = 1/(4\pi \epsilon_0) * (q_1 * q_2)/r

But I don't understand how to calculate the energy for a grid with an infinite amount of charges. Can someone point me in the right direction please? I'm not asking for a solution, just for a small hint which will guide me in the correct direction.
 
Last edited:
Physics news on Phys.org
not too sure, but if they are alternating then the electric potential energy of one of the "particles" on the left will be equal in magnitude, but opposite in direction to the one on the right, so summing the electric potential energies for all the particles, would give you zero overall... i think, that would be my logic anyway.
 
I don't think it's that easy, but thanks for the answer. :)
 
I have arrived at the following equation now:

\phi = k * \sum_{n=1}^{\inf} 1/n * (-1)^{n+1} * q/r

However, this doesn't seem to make sense to me since -1^n+1 doesn't converge. Did I make an error in my calculations or am I missing something?
 
Never mind, figured it out. :)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
1K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
64
Views
5K
Replies
28
Views
4K
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K