How to Calculate Flow Rate with Given Parameters?

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To calculate the flow rate of water from a tank, start by considering the potential energy from the height (12m) using the formula ρgh, which converts into kinetic energy represented by 1/2ρV². Account for frictional losses over the pipe length (200m) using the frictional resistance energy loss formula: ½ ρ*f (L/d) x (V²), where f is the friction factor, L is the length, and d is the diameter. Additionally, include energy losses from fittings using the K factor with the formula ½ ρ*K*V². This combined approach will guide you toward finding the flow rate in kg/s. Understanding these principles will help clarify the calculation process.
Sevy35
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I'm trying to get my head around this question but having missed a few lecture through illness I'm going round in circles.

Water is fed from a tank 12m above ground along a pipe 200 m long with a diameter of 125mm. Pipe frictyion factor is 0.008. K factors for the fittings, (tank exit, valve etc) add up to 3.3. I'm being asked to find the flow rate in kg/s and donlt knwo where to start.

I don't want the answer, just some direction of how to approach it.

Regards

Sevy.
 
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Welcome to PF.

Basically you are going to have the potential energy of the drop (12m) that is given in ρgh that will go into kinetic energy of the flowing liquid that will be 1/2ρV².

But that's not all it goes into because they have given you the frictional factor that will be experienced over the 120m of run length. And you have the K factor for the pipe system that takes into bends and such that they would give you of 3.3.

The contribution to friction loss I think looks like

Frictional resistance energy loss = ½ ρ*f (L/d) x (V²)

L is Length and d is diameter and f is your frictional factor.

The K factor contributes an additional energy loss of ½ ρ*K*V²

where K is your K factor.
 
Here is a lecture that touches on some of the basics. (About 30 minutes in.):

https://www.youtube.com/watch?v=ngABxM7jl0Q
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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