How to Calculate Force on a Perpendicular Finite Wire Near an Infinite Wire?

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SUMMARY

The discussion focuses on calculating the force exerted on a finite conducting wire positioned perpendicularly to an infinite wire. The formula used is F = I_f ∫(μ₀ I_i / 2πr) dr, where I_f and I_i represent the currents in the finite and infinite wires, respectively. The integration is performed over the length of the finite wire, with the infinite wire aligned along the y-axis and the finite wire along the x-axis. The magnetic field B due to the infinite wire at a point x on the x-axis is expressed as B_i = k * I_i / x, where k = μ₀ / 2π, leading to the force calculation dF = I_f * B_i * (sin 90) dx = k * I_f * I_i * dx / x.

PREREQUISITES
  • Understanding of electromagnetism principles, specifically the Biot-Savart law.
  • Familiarity with the concept of magnetic fields generated by current-carrying wires.
  • Knowledge of calculus, particularly integration techniques.
  • Basic understanding of vector directions in three-dimensional space.
NEXT STEPS
  • Study the Biot-Savart law in detail to understand magnetic field calculations.
  • Learn about the integration of vector fields in electromagnetism.
  • Explore applications of magnetic forces in engineering contexts.
  • Investigate the effects of varying current magnitudes on force calculations in wire configurations.
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Students in physics or electrical engineering, educators teaching electromagnetism, and professionals working with electromagnetic systems will benefit from this discussion.

cscott
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Homework Statement



I want the force on a finite conducting wire that is perpendicular to an infinite wire.

Can I do it with this:

F = I_f \int{\frac{\mu_0 I_i}{2\pi r}}{dr} where I_f, I_i are the currents in the finite and infinite wires.
 
Last edited:
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Yes, that’s the way to do it. But what is the region of integration? It would be easier to answer if you had described the exact picture you had in mind. Why is Ii inside the integral? I presume you are dealing with steady currents.

Let’s set it up properly. Suppose the infinite wire lies along the y-axis and Ii is toward +ve y-axis. The finite wire lies on the x-axis from x1 to x2 and If is toward the +ve x-axis.

B due to Ii at a pt x on the x-axis =Bi = k*Ii/x, where I’ve written k for mu_0/2pi. Bi points in the –z dircn.

If we consider an elementary length dx at x, then the force on this is dF = If*Bi*(sin 90)dx = k*If*Ii*dx/x

Now you can integrate from x1 to x2 and tell us the magnitude and direction of the force?
 

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