How to Calculate Heat Loss Per Hour Through a Glass Window Pane?

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SUMMARY

The discussion focuses on calculating heat loss through a glass window pane measuring 2.7 m high, 2.4 m wide, and 2 mm thick, with an inner surface temperature and an outer surface temperature of 4°C. The key formula derived is P = k A ΔT, where P represents power loss, A is the area of the window, ΔT is the temperature difference, and k is a material-specific constant. It is established that heat loss increases with both the area of the window and the temperature difference, indicating a direct proportionality. Understanding the relationship between thermal conduction and thermal resistance is crucial for accurate calculations.

PREREQUISITES
  • Understanding of thermal conduction principles
  • Familiarity with the concept of temperature difference (ΔT)
  • Knowledge of the formula for power loss in thermal systems
  • Basic mathematical skills for area calculations
NEXT STEPS
  • Research the thermal conductivity values for different glass types
  • Learn about thermal resistance and its impact on heat loss calculations
  • Explore advanced heat transfer equations in building physics
  • Investigate insulation materials and their effectiveness in reducing heat loss
USEFUL FOR

Engineers, architects, and students studying building physics or energy efficiency who are interested in understanding heat loss through windows and improving thermal performance in structures.

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Homework Statement



A glass window pane is 2.7 m high, 2.4 m wide and 2 mm thick. The temperature at the inner surface of the glass is and at the outer surface 4°C. How much heat is lost each hour through the window?



The Attempt at a Solution



I have the stats on the glass like specific heat ect.

Im not quite sure what equations to use to solve this
 
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How would you expect the power lost to depend on the area of the window and the temperature difference?

Do you know the equation for electrical resistance of a material? How is this similar?
 
no, I am not quite sure what that equation is.
 
You can work it out simply.

You expect the heat loss to go up with more area - double the area = double the heat loss.
And you expect it be proportional to the temperature difference, double the temperature difference double the heat loss.

so you have power is proprtional to area * temperature differences
or P = k A dt
where k is some constant for your material

Depending on how your data is given 'k' might be thermal conduction = bigger number is more heat lost, or thermal resistance = small number is more heat lost, so you migth have K or 1/K in the equation. You can tell from the units given for 'k'
 

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