How to Calculate Impact Distance in Ballistic Motion with Given Energy?

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SUMMARY

The discussion focuses on calculating the impact distance of a ballistic motion scenario involving a steel ball with a mass of 10.2 g, launched from a height of 18 cm (h1) and impacting at a height of 35 cm (h2). The energy input (UNC) is given as 0.00216 J. The correct formula for calculating the impact distance (l) is derived from the equation l² = ((20/7)(h1 - (UNC/mg))h2). The user initially calculated an impact distance of 42.43 cm but encountered discrepancies due to unit conversion issues. Proper conversion to SI units is essential for accurate results.

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  • Understanding of ballistic motion principles
  • Familiarity with energy concepts in physics
  • Proficiency in unit conversion, particularly between grams and kilograms
  • Knowledge of gravitational acceleration (g = 9.81 m/s²)
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This discussion is beneficial for physics students, educators, and anyone involved in mechanics or projectile motion analysis, particularly those working on homework or practical applications of ballistic calculations.

sheri1987
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Homework Statement



The start point of a ballistic launcer is h1 = 18 cm above its launch point (including the correction for the starting angle) and the launch point is h2 = 35 cm above the bench top. A steel ball rolled down the launcher has a mass of 10.2 g. Answer the following question:


Calculate the impact distance when UNC = 0.00216 J. Express your answer in cm

Homework Equations



l^2 = ((20/7)(h1-(UNC/mg))h2
l = impact distance
g= gravity 9.81
m= 10.2 g
h1 = 18 cm
h2 = 35 cm
UNC = given

The Attempt at a Solution



I plugged in the numbers and solved for l (impact distance) and got ) 42.43 cm, but for some reason the computer program I am plugging it into says its wrong. Can you help me out please? Thanks!
 
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I don't get 42.43 cm, though I get something similar when i start leaving the units in the form they're in.

Mass is given in grams and h1 and h2 in cm.. convert all to SI units and then back to cm. The formula is a wee bit more complicated than need be... since 35cm = 0.35m = 7/20 you only need worry about h1 - (UNC/mg) = l^2

If this is your only concern then i hope this sorts things out... I'm not quite sure i understand the problem myself but as far as plugging numbers into that formula there seems to definitely be some issues with units...
 

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